Answer:
Part 1) The domain of the quadratic function is the interval (-∞,∞)
Part 2) The range is the interval (-∞,1]
Step-by-step explanation:
we have
This is a quadratic equation (vertical parabola) open downward (the leading coefficient is negative)
step 1
Find the domain
The domain of a function is the set of all possible values of x
The domain of the quadratic function is the interval
(-∞,∞)
All real numbers
step 2
Find the range
The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.
we have a vertical parabola open downward
The vertex is a maximum
Let
(h,k) the vertex of the parabola
so
The range is the interval
(-∞,k]
Find the vertex
Factor -1 the leading coefficient
Complete the square
Rewrite as perfect squares
The vertex is the point (7,1)
therefore
The range is the interval
(-∞,1]
Answer:
7
Step-by-step explanation:
The initial value is another name for the y-intercept. This equation is written in point slope form (y=mx+b). And before you think y-intercept means y, right? No that is incorrect, I got that wrong in the beginning too ;)
y=mx+b
y=8x+7
b in the point slope form equation is always the initial value or y-intercept or whatever people call it. So what substitutes b out here? 7. So 7 is the initial value!
:) Hope you understand now! Have a good day!
Answer:
y = 2/3x + 4
Step-by-step explanation:
First, we look at where the equation intersects the y axis. It intersects at y = 4, which means that in the end of the equation there must be a "+4", so we can rule out the first two.
Second, we look at the slope of the line. Slope is defined as rise over run. As you can see in the graph, the line moves up 2 units while moving right 3 units. That means the coefficient of x (which is the slope) will be 2/3, which means the answer is y = 2/3x + 4.
Answer:xcvxvxcvxcvxcvc
Step-by-step explanation:
bcvbcvbcvb
We will find the inverse of the given functions:
y = x + 2 / x-2
(x-2) y = x + 2
-2y + xy = x + 2
-2y + xy = x + 2
x (y - 1) = 2 + 2y
x (y - 1) = 2 (y + 1)
x = 2 (y + 1) / (y - 1)
f (x) ^ - 1 = 2 (x + 1) / (x - 1)
The inverse is different.
f (x) = x + 1 / x-1
y = x + 1 / x-1
(x-1) y = x + 1
-y + xy = x + 1
x (y - 1) = 1 + y
x (y - 1) = (y + 1)
x = (y + 1) / (y - 1)
f (x) ^ - 1 = (x + 1) / (x - 1)
The inverse is the same.
Answer:
f (x) = x + 1 / x-1
f (x) ^ - 1 = (x + 1) / (x - 1)
f (x) = f (x) ^ - 1
