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dusya [7]
3 years ago
6

The changing climate will probably bring more rain to California, but we don't know whether the additional rain will come during

the winter season or extend into the long dry season in spring and summer. Kenwyn Suttle of the University of California at Berkeley and his coworkers wanted to compare the effects of three treatments: added water equal to 20% of annual rainfall either during January to March (winter) or during April to June (spring), and no added water (control). Eighteen plots of open grassland, each with area 70 square meters, were available for this study. One response variable was total plant biomass, in grams per square meter, produced in a plot over a year. Describe a completely randomized design for this experiment. Write a few sentences describing how you would implement your design.
Mathematics
1 answer:
Taya2010 [7]3 years ago
3 0

Answer:

Number each of the treatments 1 — 3 and place them into a hat.

Step-by-step explanation:

Number each of the treatment I — 3 and place them into a hat. Shake the hat vigorously to mix the lumbers. Then for each plot of land, draw out a umber. The number drawn out from the hat will represent the treatment that will be imposed on the plot.

The number drawn out of the hat will be replaced and another number will be drawn for the next plot of land. Then, at the end of the experiment, the plant biomass of each plot will be measured and an average will be taken for all three treatments to determine which treatment had the greatest effect on plant biomass.  

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Three times the square of a non-zero number is equal to fifteen times the number.what is the number?
Alona [7]
5 because you subtract 15x and bring it to 3x^2 and get 3x^2-15x=0. Then take out the gcf and you get 3x(x-5)=0. Since it can't be 0, x-5=0 , the answer is 5.
8 0
3 years ago
Katie is going to a carnival and received $50 from her mother to spend. At the carnival, entry costs $12.00 and ride tickets cos
nlexa [21]

Answer: See explanation

Step-by-step explanation:

Your question isn't complete but I believe that you want to know the number of rides that Katie can take.

Based on the information in the question, we can form an equation. Let the number of rides that Katie can take be represented by x. Therefore,

12 + (1.25 × x) = 50

12 + 1.25x = 50

1.25x = 50 - 12

1.25x = 38

x = 38/1.25

x = 30.4

Therefore, Katie can take at most 30 rides.

3 0
2 years ago
A circular garden has a diameter of 20 yards. What is the area of the garden to the
marissa [1.9K]

Answer:314

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4 0
3 years ago
Whats the soultion for 10000 ft/hr = mi/hr
VLD [36.1K]
Hi! There are 5,280 feet in a mile. Therefore, you need to divide 10,000 feet by 5,280 (to see how many miles there are per every 5280 feet) and you get 1.89 miles per hour.
7 0
2 years ago
An investment of $8,000 earns interest at an annual rate of 7% compounded continuously. Complete parts (A) and (B) below. Click
Sergeeva-Olga [200]

Answer:

A.    \mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}

B.    \mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }

Step-by-step explanation:

Given that:

An investment of  Amount = $8000

earns  at an annual rate of interest = 7% = 0.07 compounded continuously

The objective is to :

A)  Find the instantaneous rate of change of the amount in the account after 2 year(s).

we all know that:

A = Pe^{rt}

where;

A = (8000) \ e ^{0.7t}

The instantaneous rate of change = \dfrac{dA}{dt}

\dfrac{dA}{dt} = \dfrac{d}{dt}(8000 \ e ^{0.07t} )

= 8000 \dfrac{d}{dt}e^{0.07 \ t}

\dfrac{dA}{dt}= 8000 (0.07)e^{0.07 \ t}

\dfrac{dA}{dt}= 560 e^{0.07 \ t}

At t = 2 years; the instantaneous rate of change is:

\dfrac{dA}{dt}|_{t=2}= 560 e^{0.07 \times 2}

\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}

(B) Find the instantaneous rate of change of the amount in the account at the time the amount is equal to $12,000.

Here the amount = 12000

12000 = (8000)e^{0.07 \ t}

\dfrac{12000 }{8000}= e^{0.07 \ t}

1.5= e^{0.07 \ t}

㏑(1.5) = 0.07 t

0.405465 = 0.07 t

t = 0.405465 /0.07

t = 5.79

\dfrac{dA}{dt}= 560 e^{0.07 \ t}

At t = 5.79

\dfrac{dA}{dt}|_{t = 5.79}= 560 e^{0.07 \times 5.79}

\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }

7 0
3 years ago
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