9514 1404 393
Answer:
a) E = 6500 -50d
b) 5000 kWh
c) the excess will last only 130 days, not enough for 5 months
Step-by-step explanation:
<u>Given</u>:
starting excess (E): 6500 kWh
usage: 50 kWh/day (d)
<u>Find</u>:
a) E(d)
b) E(30)
c) E(150)
<u>Solution</u>:
a) The exces is linearly decreasing with the number of days, so we have ...
E(d) = 6500 -50d
__
b) After 30 days, the excess remaining is ...
E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days
__
c) After 150 days, the excess remaining would be ...
E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system
The supply is not enough to last for 5 months.
Answer:
1595 ft^2
Step-by-step explanation:
The answer is obtained by adding the areas of sectors of several circles.
1. Think of the rope being vertical going up from the corner where it is tied. It goes up along the 10-ft side. Now think of the length of the rope being a radius of a circle, rotate it counterclockwise until it is horizontal and is on top of the bottom 20-ft side. That area is 3/4 of a circle of radius 24.5 ft.
2. With the rope in this position, along the bottom 20-ft side, 4.5 ft of the rope stick out the right side of the barn. That amount if rope allows for a 1/4 circle of 4.5-ft radius on the right side of the barn.
3. With the rope in the position of 1. above, vertical and along the 10-ft left side, 14.5 ft of rope extend past the barn's 10-ft left wall. That extra 14.5 ft of rope are now the radius of a 1/4 circle along the upper 20-ft wall.
The area is the sum of the areas described above in numbers 1., 2., and 3.
total area = area 1 + area 2 + area 3
area of circle = (pi)r^2
total area = 3/4 * (pi)(24.5 ft)^2 + 1/4 * (pi)(4.5 ft)^2 + 1/4 * (pi)(14.5 ft)^2
total area = 1414.31 ft^2 + 15.90 ft^2 + 165.13 ft^2
total area = 1595.34 ft^2
Im assuming you mean 20pence? if so its 5 twenty pence in a pound so times 5 by 9 gives you 45
so there are 45 twenty pence in £9
None of above is the answer
