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3 years ago

Solve x 3x+6=42 please help me get this done

Mathematics

2 answers:

fiasKO [112]3 years ago

5 0

Answer:

this can be solved by using transposition method let me tell you how

Step-by-step explanation:

3x+6=42

+6 will transpose to the rhs

=3x = 42 - 6 (+WILL BECOME - WHILE TRANSPOSING LHS TO RHS)

= 3x = 36

3x will transpose and will become division

= x = 36 /3

=x =12

the value of x is 12

Nikitich [7]3 years ago

4 0

_______________________________

Solution,

3x+6=42

or,3x=42-6

or, 3x=36

or,X=36/3

X=12

The value of X is 12.

hope it helps

Good luck on your assignment

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2 years ago

20 points and Brainliest if answered and explained!

Rasek [7]

What you need to know for this case is that the sum of the internal angles of a triangle is 180 °
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3 years ago

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netineya [11]

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8 0

3 years ago

Read 2 more answers

For ΔABC, ∠A = 2x - 2, ∠B = 2x + 2, and ∠C = 5x. If ΔABC undergoes a dilation by a scale factor of 1 2 to create ΔA'B'C' with ∠A

Zolol [24]

<h3>Answer:</h3>

A) ∠A = ∠A' = 38° and ∠B = ∠B' = 42°

<h3>Explanation:</h3>

The sum of angles in ∆ABC is 180°, so ...

... (2x -2) + (2x +2) + (5x) = 180

... 9x = 180

... x = 20

and the angles of ∆ABC are ∠A = 38°, ∠B = 42°, ∠C = 100°.

___

The sum of angles of ∆A'B'C' is 180°, so ...

... (58 -x) +(3x -18) +(120 -x) = 180

... x +160 = 180

... x = 20

and ∠A' = 38°, ∠B' = 42°, ∠C' = 100°.

_____

The values of angle measures of ∆ABC match those of ∆A'B'C', so we can conclude ...

... A) ∠A = ∠A' = 38° and ∠B = ∠B' = 42°

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