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Ivenika [448]
2 years ago
9

PLEASE I NEED THE ANSWER (JUST THE ANSWER)

Mathematics
1 answer:
earnstyle [38]2 years ago
4 0
The answer should be number one. (No correlation)
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Solve the equation for r. 2x+34=4(x+5)
Rainbow [258]

Answer:

7=x

Step-by-step explanation:

2x+34=4(x+5)

2x+34=4x+20

-2x       -2x          

34=2x+20

-20      -20

14=2x

/2   /2

6 0
3 years ago
Read 2 more answers
I need help hurry!!<br> Show ur work pls 5-10
7nadin3 [17]

Answer:

5. y=\frac{1}{3}x-3

6. y=\frac{1}{4}x+4

7. y=-5

8. y=x+5

9. y=\frac{-1}{2}x+6

10.y=-4x+2

Step-by-step explanation:

5. Slope = \frac{-1-0}{6-9} = \frac{-1}{-3} = \frac{1}{3}

y=\frac{1}{3} x+b\\0=\frac{1}{3}(9)+b\\0=3+b\\b=-3

6. Slope => \frac{2-6}{-8-8}  = \frac{-4}{-16} = \frac{1}{4}

y = \frac{1}{4} x+b

6=\frac{1}{4}(8)+b\\6=2+b\\b=4

7. Slope => \frac{-5-(-5)}{-4-7}=\frac{0}{-11} =0

y=-5

8. Slope => \frac{4-7}{-1-2} = \frac{-3}{-3} = 1

y=x+b\\7=2+b\\b=5

9. Slope => \frac{10-4}{-8-4} = \frac{6}{-12}= \frac{-1}{2}

y=\frac{-1}{2}x+b\\4= \frac{-1}{2}(4)+b\\4=-2+b\\b=6

10. Slope => \frac{14-2}{-3-0} =\frac{12}{-3} =-4

y=-4x+b\\2=-4(0)+b\\b=2

3 0
3 years ago
I can't figure out how to find the cubed root
andreev551 [17]
I hope this helps you

7 0
3 years ago
Solve this differential equation using power series and indicial roots about (0,0):
Ivanshal [37]
Let y=\displaystyle\sum_{k\ge0}a_kx^k, so that

y'=\displaystyle\sum_{k\ge1}ka_kx^{k-1}
y''=\displaystyle\sum_{k\ge2}k(k-1)a_kx^{k-2}

Substituting into the ODE gives

\displaystyle3x\sum_{k\ge2}k(k-1)a_kx^{k-2}+6\sum_{k\ge1}ka_kx^{k-1}+\sum_{k\ge0}a_kx^k=0
\displaystyle3\sum_{k\ge2}k(k-1)a_kx^{k-1}+6\sum_{k\ge1}ka_kx^{k-1}+\sum_{k\ge0}a_kx^k=0

The first series starts with a linear term, while the other two start with a constant. Extract the first term from each of the latter two series:

\displaystyle6\sum_{k\ge1}ka_kx^{k-1}=6\sum_{k\ge2}ka_kx^{k-1}+6a_1
\displaystyle\sum_{k\ge0}a_kx^k=\sum_{k\ge1}a_kx^k+a_0

Finally, to get the series to start at the same index, shift the index of the first two series by replacing k with k+1. Then the ODE becomes

\displaystyle3\sum_{k\ge1}k(k+1)a_{k+1}x^k+6\sum_{k\ge1}(k+1)a_{k+1}x^k+\sum_{k\ge1}a_kx^k+6a_1+a_0=0

which can be consolidated to get

\displaystyle\sum_{k\ge1}\bigg[(3k(k+1)+6(k+1))a_{k+1}+a_k\bigg]x^k+6a_1+a_0=0
\displaystyle\sum_{k\ge1}\bigg[3(k+1)(k+2)a_{k+1}+a_k\bigg]x^k+6a_1+a_0=0

You're fixing the solution so that it contains the origin, which means

y(0)=\displaystyle\sum_{k\ge0}a_kx^k=a_0=0

which in turn means a_1=0. With the given recurrence, it follows that a_k=0 for all k\ge2, so the solution would be y=0. This is to be expected, since x=0 is clearly a singular point for the ODE.
8 0
3 years ago
Please do 13 ive been trying for 3 hour pls solve x
Zepler [3.9K]

Answer:

<u>x = 3</u>

Step-by-step explanation:

We should know that:

A straight segment joining the middle of two sides in a triangle is parallel to the third side and equal to half of it.

So,

3x + 1 = (1/2) * 20 = 10

3x = 10 - 1 = 9

x = 9/3 = 3

<u>So, the value of x = 3</u>

5 0
3 years ago
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