Answer:
Here is a graph I created.
For Miguel to spend the least amount of money, he would have to buy 2 gallons for $5.98 and two 1/2 gallons for $4.20. The total is $10.18.
I'm stuck on the next question though.
The lowest term is
.
Solution:
Given expression is 
<u>To reduce this term to the lowest term:</u>

Multiply the numerator and denominator.

Now, divide the numerator and denominator by the greatest common factor.
Here 150 and 8 both have common factor 2.
So, divide numerator and denominator by 2.



Hence the lowest term is
.
Answer:
29 × 51 inches
Step-by-step explanation:
If the scale is ...
photo : painting = 1 : 3
then each dimension of the painting is 3 times the corresponding dimension of the photo. The painting is (3×13) by (3×17) inches, or 39 × 51 inches.
Answer:
B. $39550
Step-by-step explanation:
The expression for the function is not well-formatted, find the correct format in the solution bellow
Step one:
given data
We are told that the function of the cost is

instantaneous rate c(t) is the value obtained when we plug in 100 for t in the function above
substituting we have

$39550