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Andrews [41]
2 years ago
5

How do you subtract -5000 from 263

Mathematics
2 answers:
Zarrin [17]2 years ago
7 0

Answer:

263-5000=4737

Step-by-step explanation:

monitta2 years ago
3 0

IF ITS -5000-263

if you subtract a negative to a negative it makes the negative increase. -5000-263 would end up being technically -5000+(-263). A number line would help you, because on a number line, when subtracting, you go to the left.

<em><u>[-5000+(-263)=-5263]</u></em>

IF ITS 263-(-5000)

do you see those two - signs? Those cross eachother out, turning it into a +, also making the -5000 not negative anymore. Making 263-(-5000) = 263+5000.

<em><u>[263+5000=5263]</u></em><em><u> </u></em>

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A point has zero dimension. True or False?
djverab [1.8K]

Answer:

True

Step-by-step explanation:

A point is zero-dimensional with respect to the covering dimension because every open cover of the space has a refinement consisting of a single open set.

7 0
3 years ago
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4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.
nikitadnepr [17]

Answer:

\sum_{n=0}^9cos(\frac{\pi n}{2})=1

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}

Step-by-step explanation:

\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))

=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})

=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1

2nd

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}

=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0

3th

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))

=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}

What we use?

We use that

e^{i\pi n}=cos(\pi n)+i sin(\pi n)

and

\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}

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3 years ago
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5 0
3 years ago
I can't get to get this right can you please help me​
monitta

Answer:

(-7,4]\text{ or }\{x|-7

Step-by-step explanation:

The domain is the span of x-values covered by the function.

From the graph, we can see that the graph covers all the x-values from x=-7 to x=4.

However, note that closed and open circles. There is an open circle at x=-7, which means that the domain excludes x=-7. However, the circle at x=4 is closed, meaning it is included in the domain.

Therefore, the domain is, in interval notation:

(-7,4]

We use parentheses on the left because we do not include -7. And we use brackets on the right because we <em>do </em>include the 4.

And in set notation, this is:

\{x|-7

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Answer:

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Step-by-step explanation:

Source: just trust me bro

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