They are not because 1/2 you cannot multiply it by anything to get 1/8
Answer:
0.6710
Step-by-step explanation:
The diameters of ball bearings are distributed normally. The mean diameter is 107 millimeters and the population standard deviation is 5 millimeters.
Find the probability that the diameter of a selected bearing is between 104 and 115 millimeters. Round your answer to four decimal places.
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean = 107 mm
σ is the population standard deviation = 5 mm
For x = 104 mm
z = 104 - 107/5
z = -0.6
Probability value from Z-Table:
P(x = 104) = 0.27425
For x = 115 mm
z = 115 - 107/5
z = 1.6
Probability value from Z-Table:
P(x = 115) = 0.9452
The probability that the diameter of a selected bearing is between 104 and 115 millimeters is calculated as:
P(x = 115) - P(x = 104)
0.9452 - 0.27425
= 0.67095
Approximately = 0.6710
Answer:
100%
Step-by-step explanation:
Probability of a product showing up in warehouse A =60%
Probability of a product showing up in warehouse B = 80%
Probability of 2 product showing up in warehouse A is
Probability of 1 product showing up in A and probability of 1 product showing up in A
A n A = 60% x 60% = 0.6 x 0.6 = 0.36 =36%
Probability of 2 product showing up in warehouse B is
Same as above
Probability of 1 product showing up in B and probability of 1 product showing up in B
B n B = 80% x 80% = 0.8 x 0.8 = 0.64= 64%
Probability of 2 product showing up in same warehouse is define as
Probability of 1 product showing up in A and probability of 1 product showing up in A or
Probability of 1 product showing up in B and probability of 1 product showing up in B
(AnA) U (BnB) =
36% + 64% = 0.36 + 0.64= 1
100%
