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2 years ago

HELP!!! please this is my last question for my paper

Mathematics

1 answer:

s2008m [1.1K]2 years ago

4 0

Answer:

$\sqrt{2}$

Step-by-step explanation:

We can use pytho theorem to find X because its a right triangle, so:

a^2 + b^2 = c^2

plug our numbers

1^2 + 1^2 = x^2

simplify

1+1 = x^2

2=x^2

answer = root2

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what is the value of the reciprocal of $\frac{-2}{5}$? express your answer as a decimal to the nearest tenth.

olga2289 [7]

The reciprocal of -2/5, expressed as a decimal to the nearest tenth is: -2.5.

<h3>What is the Reciprocal of a Number?</h3>

The reciprocal of a number can be described as the inverse of that number. For example, if a is given as a real number, therefore, the reciprocal of a would be 1/a.

Another example is a/b. The reciprocal of a/b is b/a.

Thus, the reciprocal of -2/5 is -5/2.

Expressing this as a decimal, we would have:

-5/2 = 2.5 (nearest tenth).

Therefore, the reciprocal of -2/5, expressed as a decimal to the nearest tenth is: -2.5.

Learn more about the reciprocal of a number on:

brainly.com/question/20896748

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6 0

1 year ago

Question is in the attachment

ruslelena [56]

Sorry I can’t see the pic

6 0

2 years ago

X*2+1=10 then x=? Tell me the value of x

Trava [24]

Answer:

Step-by-step explanation:

$x \times 2 + 1 = 10$

$2x + 1 = 10$

Move constant to R.H.S and change its sign

$2x = 10 - 1$

Subtract the numbers

$2x = 9$

Divide both sides of the equation by 2

$\frac{2x}{2} = \frac{9}{2}$

Calculate

$x = 4.5$

Hope this helps..

Best regards!!

6 0

3 years ago

Lim x-1 x2 - 1/ sin(x-2)

balu736 [363]

Answer:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0$

Explanation:

Assuming the correct expression is to find the following limit:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}$

Use the property the limit of the quotient is the quotient of the limits:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}$

Evaluate the numerator:

$\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}$

Evaluate the denominator:

Since $\lim_{x \to1}sin(x-2)\neq 0$

$\frac{0}{\lim_{x \to1}sin(x-2)}=0$

4 0

2 years ago

Amaya is excited to go to the used video game store to buy a game system later today. The game system usually costs x dollars, b

Ksenya-84 [330]

Answer:

x(85/100)

Step-by-step explanation:

100-15 = 85

x(85/100)

5 0

2 years ago

Read 2 more answers