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cricket20 [7]
4 years ago
14

The lines below are parallel if the slope of the green line is -2 what is the slope of the red line

Mathematics
1 answer:
kati45 [8]4 years ago
8 0

Answer:

-2

Step-by-step explanation:

Since they are parallel, they have the same slope. This will be true for any set of lines.

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3 (n + 7) = __ + 21<br> Answer?
ElenaW [278]

Answer:

3n

Step-by-step explanation:

We can see that the 3 gets distributed into the parentheses since there is a +21 on the right (3×7=21) so we also have to distribute the 3 to the n

5 0
3 years ago
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A salesman earns 30% commission on the merchandise that he sells last month he sold $600 worth of merchandise how much of commis
romanna [79]

Answer:

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.3 * 600

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3 years ago
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How do i solve 5y - 10 = -25?
viva [34]
So to find the answer you want to isolate the y. So the first thing you want to do is to move everything to the opposite side of the = sign. You start by adding 10 to both sides.
10+ 5y -10 = -25 +10  
 5y = -15.
the tens cancel out on the left side and on the right you get left with -15/
Since y is being multiplied by 5 you always want to do the opposite so you divide by 5.
5y/5 = -15/5
y = -3
It's hard to explain but you just have to remember that what you do to one side you must do to the other to keep the equation balanced.

8 0
4 years ago
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How do I do this I need help right now
kodGreya [7K]
To answer this (specifically the first one) you have to count how many spaces each point moves. (How many spaces up/down does it go? Left/right?) then you put rise (up/down) over run (left/right) and you should get the slope!
6 0
3 years ago
Need help now!! 20 points!!
Gelneren [198K]

When you have something like this, all you need to do is substitute the values, the last is for what value of x

For the first one;

((x^2+1)+(x-2))(2)

(x^2+x-1)(2)

(2)^2+(2)-1

4+2-1

5

For the second one;

((x^2+1)-(x-2))(3)

(x^2-x+3)(3)

(3)^2-(3)+3

9-3+3

9

For the last one;

3(x^2+1)(7)+2(x-2)(3)

3((7)^2+7)+2((3)-2)

3(49+7)+2(3-2)

3(56)+2(1)

168+2

170

3 0
3 years ago
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