With any equation you are allowed to take the logarithm of both sides so
5^c=125 now take the logarithm base 5 to both sides giving.
log5(5^c)=log5(125), using the rule log(a^b)=a*log(b) you get
c log5(5)=log5(125), since log5(5)=1
c=log5(125)
Answer:
All real numbers except x cannot equal 10.
Step-by-step explanation: the denominator can not equal to zero that is undefined.
Answer: The starting time is 2:27 and finishing time is 7:09.
Step-by-step explanation: It is given that Ben started from 4th street and he finished at 98th street.
Also, at 3:00, he was on 15th street and at 4:30, he was on 45th street.
That is, time taken to cover (45-15), i.e., 30 streets is 90 minutes, so the time taken to cover 1 street is 3 minutes.
Therefore, Ben covers distance from one street to second in 3 minutes. Since he started from 4th street, and there are 11 streets to cover between 4 and 15, so Ben's starting time was (3:00 - 3×11 min) = 2:27.
And his finishing time was (4:30 + 3×53 min) = 7:09.
Again, the equation that tells us on what street 'N' he was after time 'T' of his starting can be written as

Thus, the starting and finishing time was 2:27 and 7:09 respectively.
32 pints is the answer to this question
Answer:
10 points
Step-by-step explanation:
Points scored in each of the first 3 quarter = x
Total points scored in the first 3 quarter = x + x + x
= 3x
Points scored in the fourth quarter = 14
Total points scored = 44 point
Total points scored = Total points scored in the first 3 quarter + Points scored in the fourth quarter
44 = 3x + 14
Subtract 14 from both sides
44 = 3x + 14
44 - 14 = 3x + 14 - 14
30 = 3x
Divide both sides by 3
x = 30/3
= 10
x = 10 points
Points scored in each of the first 3 quarter = x = 10 points
The school football team scored 10 points points in the first quarter