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Blizzard [7]
3 years ago
7

60 points Math Question 2 of 10 Select the two values of x that are roots of this equation.

Mathematics
2 answers:
Vaselesa [24]3 years ago
8 0
☁️Answer☁️

The answers are -1+ square root of 7 and -1- square root of 7. In other words the answers are options B and D.

Hope this helps ;)
Pie3 years ago
3 0

Answer:

  • B and D

Step-by-step explanation:

<u>Solve the equation by completing a square:</u>

  • x² + 2x - 6 = 0
  • x² + 2x + 1 - 7 = 0
  • (x + 1)² = 7
  • x + 1 = ±√7
  • x = -1 ± √7

<u>Correct choice:</u>

  • B and D

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If y-3x=9, 7x+y=25, what is the value of x and y?
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\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
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Answer:

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