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aliina [53]
2 years ago
13

253,248,243, find the 49th term.

Mathematics
1 answer:
denpristay [2]2 years ago
8 0

Answer:

13

Step-by-step explanation:

the difference is -5

  • nth=a+(n-1)d
  • a=253,n=49,d=5
  • 253+(49-1)×-5
  • 253+48×-5
  • 253+(-240)
  • 253-240=13

the 49th term is 13

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Minimum point of the quadratic x^2+6x-2
WITCHER [35]

Answer:

(-3,-11)

Step-by-step explanation:

Compare the given quadratic equation with the general quadratic equation.

a=1, b=6 and c=-2

x=-\dfrac{(6)}{2(1)}\\=-3

Subsitute -3 for x in given quadratic equation.

y=(-3)^2+6(-3)-2\\=9-18-2\\=-11

The minimum point is (-3,-11).

3 0
2 years ago
Each students in class 38 students was asked to report how many siblings he has. Data a 0/38 Data b 1/38 Data c 13/38 Data 8/38
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8/38

Step-by-step explanation:

You got it right, trust yourself

4 0
3 years ago
According to a marketing research study, American teenagers watched 14.8 hours of social media posts per month last year, on ave
ki77a [65]

Answer:

The value of test statistics is 1.06.

Step-by-step explanation:

We are given that according to a marketing research study, American teenagers watched 14.8 hours of social media posts per month last year, on average. A random sample of 11 American teenagers was surveyed and the mean amount of time per month each teenager watched social media posts was 15.6. This data has a sample standard deviation of 2.5.

We have to test if the mean amount of time American teenagers watch social media posts per month is greater than the mean amount of time last year or not.

Let, NULL HYPOTHESIS, H_0 : \mu = 14.8 hours  {means that the mean amount of time American teenagers watch social media posts per month is same as the mean amount of time last year}

ALTERNATE HYPOTHESIS, H_1 : \mu > 14.8 hours  {means that the mean amount of time American teenagers watch social media posts per month is greater than the mean amount of time last year}

The test statistics that will be used here is One-sample t-test;

             T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean amount of time per month each teenager watched social media posts = 15.6 hours

             s = sample standard deviation = 2.5 hours

             n = sample of teenagers = 11

So, <u>test statistics</u> =  \frac{15.6 - 14.8}{\frac{2.5}{\sqrt{11} } } ~ t_1_0

                            = 1.06

Hence, the value of test statistics is 1.06.

5 0
3 years ago
Jillian surveyed students at her school and found out the following probabilities: P ( freshman ) = 0.30 P ( plays instrument )
VLD [36.1K]

Answer: 1/3

Step-by-step explanation:

6 0
3 years ago
Evaluate and simplify tan 15º.
dimulka [17.4K]
Tan(15) = tan(45 - 30) 

= [tan(45) - tan(30) ] / [ 1 + tan(30)tan(45)] 

= (1 - 1/sqrt(3)) /(1 + 1/sqrt(3)) 

= (sqrt(3) - 1)/(sqrt(3) + 1) 

= (sqrt(3) - 1)^2 /(3 - 1)

 = 1/2 [3 + 1 - 2sqrt(3) ] 

= (2 - sqrt(3) )

= 0.27 is your answer
6 0
3 years ago
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