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sp2606 [1]
2 years ago
14

Name the alkanes please help

Chemistry
1 answer:
Pie2 years ago
4 0
Methane CH4 CH4 1 hexane C6H14 CH3(CH2)4CH3 5
ethane C2H6 CH3CH3 1 heptane C7H16 CH3(CH2)5CH3 9
propane C3H8 CH3CH2CH3 1 octane C8H18 CH3(CH2)6CH3 18
butane C4H10 CH3CH2CH2CH3 2 nonane C9H20 CH3(CH2)7CH3 35
pentane C5H12 CH3(CH2)3CH3 3 decane C10H22 CH3(CH2)8CH3 75
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For sediment to be transformed into rock, which set of procces must take place?
Burka [1]

Answer:

compaction and cementation.

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3 years ago
A sample of neon effuses from a container in 38 s. The same amount of an unknown noble gas requires 77.5 s. What is the unknown
Leviafan [203]

Answer:

Krypton.

Explanation:

By Graham's Law:

Rate 1 / Rate 2 = sqrt M2 / sqrt M1

Molecular Mass for Neon  is 20.18

so we have:

38 / 77.5  =  sqrt 20.18 / sqrt x    where x is the unkown gas.

sqrt x = 9.162

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This gas is Krypton.

8 0
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TRUE or FALSE. The particles of a gas are packed closely together and don't have as much movement as the particles of a solid or
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3 years ago
when the volume of a gas is changed from 3.75 L to 6.52 L the temperature will change from 100k to blank k
Makovka662 [10]
Guy-Lussac's Law states that the volume and the temperature are directly proportional given that the pressure remains constant.

For this problem, we will assume constant pressure. Based on the law:
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4 0
4 years ago
Read 2 more answers
The rate law for the decomposition of aqueous hydrogenperoxide
Murrr4er [49]

Answer:

t_{1/2}=19.98\ min

[A_t]=0.037\ M

Explanation:

(a)

Given that:

Rate constant, k = 0.0347 min⁻¹

The expression for the half-life is:-

t_{1/2}=\frac{\ln 2}{k}

Where, k is rate constant

So,  

t_{1/2}=\frac{\ln 2}{0.0347}\ min

t_{1/2}=19.98\ min

(b)

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given that:

The rate constant, k = 0.0347 min⁻¹

t = 60 min

Initial concentration [A_0] = 0.300 M

Final concentration [A_t] =?

Applying in the above equation, we get that:-

[A_t]=0.300\times e^{-0.0347\times 60}\ M

[A_t]=0.3\times \frac{1}{e^{2.082}}\ M

[A_t]=0.037\ M

7 0
3 years ago
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