PLEASE HELP ITS DUE SOON IM SO CONFUSED! HELP NEEDED!!

Mathematics

1 answer:

ddd [48]2 years ago

6 0

Answer:

e

Step-by-step explanation:

According to Angle Sum Property :

∠A + ∠B + ∠C = 180°

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Given :

⇒ ∠A = 50°

⇒ ∠B = 32°

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Solving :

⇒ 50° + 32° + ∠C = 180°

⇒ ∠C + 82° = 180°

⇒ ∠C = 98°

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Solve the system of linear equations by substitution. 2x-y=3 x+5y=14

adoni [48]

Let 2x – y = 3 ——— equation 1

Let x + 5y = 14 ——— equation 2

Making x the subject in eqn 1, = x = y + 3 / 2 ——— eqn 3

• Put eqn 3 in eqn 2

(y + 3 / 2) + 5y = 14

6y = 14 – 3/2

6y = 25/2

y = 25/12

• put y = 25/12 in eqn 3

x = (25/12 + 3/2)

x = 43/12

4 0

3 years ago

SOMEONE PLEASE HELP!! I NEED TO GET THIS RIGHT

satela [25.4K]

Answer:

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Step-by-step explanation:

3 0

3 years ago

Simplify: cos2x-cos4 all over sin2x + sin 4x

GrogVix [38]

Answer:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

Step-by-step explanation:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}$

Apply formula:

$\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$ and

$\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$

We get:

$=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}$