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kari74 [83]
3 years ago
12

What is the greatest common factor of 15 and 45? Explain your answer.

Mathematics
1 answer:
timofeeve [1]3 years ago
6 0
Factors of 15: 1, 3, 5, 15

<span>Factors of 45: 1, 3, 5, 9, </span>15, 45

<span>The Greatest common factor is 15.</span>
You might be interested in
if there are 300 calories in 100 g of a certain food, how many calories are there in a 30 g portion of food​
kap26 [50]

Answer:

90 calories

Step-by-step explanation:

Calories : quantity of food

there are 300 calories in 100 g of a certain food

300 calories : 100 g food

how many calories are there in a 30 g portion of food​

Let x = number of calories

x calories : 30 g food

Equate both ratios

300 calories : 100 g food = x calories : 30 g food

300/100 = x/30

300 * 30 = 100 * x

9000 = 100x

x = 9000/100

x = 90

x = number of calories = 90 calories

6 0
3 years ago
Need help asap with these
IRISSAK [1]

Answer:

1. 6n - 15

2. x + 10

3. -4d + 15

4. true, associative property

5. distributive, commutative

Step-by-step explanation:

1. distribute 3/4 into the parentheses, so multiply 3/4 * 8 and 3/4 * -20

2. distribute the 2 into the parentheses so multiply 2 * 3x and 2 * 5, then combine like terms

3. distribute -3 into the parentheses so -3 * 4D and -3 * -5 then add like terms

4. add like terms on both sides of the equal sign and you get 10x on both sides. this is the associative property because it doesn't matter what's inside or outside the parentheses you get the same answer no matter how you add them up

5. the first part is distributive because you distributed the three into the parentheses and the second part is commutative because you switch them around and you can get the same answer

6 0
3 years ago
What do we call financial assistance for a student who meets academic, athletic, or talent requirements to help pay for college
sladkih [1.3K]
This is a scholarship.

Student loans must be repaid; grants are given usually without those types of restrictions; and student work involves a student having an on-campus job.
8 0
3 years ago
On Sunday Sheldon bought 3 and 1/2kg of plant food. He used 1 and 2/3kg on his strawberry plants and used 1/4kg for his tomato p
notsponge [240]

The remaining plant food is: 1 7/12 kg

Step-by-step explanation:

Given

Total Plant food = 3 1/2 kg

Plant food used on Strawberry Plants = 1 2/3 kg

Plant food used on tomato Plants = 1/4 kg

We will first calculate the total food plant used and then subtract the used plant food from the total plant food.

So,

Total\ Plant\ Food\ used=1\frac{2}{3}+\frac{1}{4}\\=\frac{5}{3}+\frac{1}{4}\\=\frac{20+3}{12}\\=\frac{23}{12}

Now,

Left\ Food\ Plant=3\frac{1}{2}-\frac{23}{12}\\=\frac{7}{2}-\frac{23}{12}\\=\frac{42-23}{12}\\=\frac{19}{12}\\=1\frac{7}{12}

The remaining plant food is: 1 7/12 kg

Keywords: Division, Fractions

Learn more about fractions at:

  • brainly.com/question/3126500
  • brainly.com/question/3306327

#LearnwithBrainly

7 0
3 years ago
B.HELPPPP MEEEE PLSSSS AND THANK YOUU
Gemiola [76]

Answer:

A. (3, 8) and 2\sqrt{2}

B. (2, 4) and 2\sqrt{10}

Step-by-step explanation:

Midpoint formula: (\frac{x1+x2}{2} ,\frac{y1+y2}{2})

Distance formula: \sqrt{(x_{2}-x_{1}) ^2+(y_{2}-y_{1}) ^2 }

A. plug in the points in the formulas

(4, 7) and (2, 9)

Midpoint:

(\frac{4 + 2}{2} , \frac{7+9}{2} )=6/2, 16/2 = (3,8)

Length:

\sqrt{(2-4)^2+(9-7)^2}=\sqrt{4+4} =\sqrt{8} =2\sqrt{2}

B.

(5, 5) and (-1, 3)

Midpoint:

(\frac{5-1}{2} , \frac{5+3}{2} )=4/2,8/2=(2,4)

Length:

\sqrt{(-1-5)^2+(3-5)^2} =\sqrt{-6^2+-2^2} =\sqrt{36+4} =\sqrt{40} = 2\sqrt{10}

Can you consider marking my answers as brainliest lol it would mean a lot. Hope this helped.

4 0
2 years ago
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