Answer:
If 
or 
, there is only one solution to the given quadratic equation.
Step-by-step explanation:
Given a second order polynomial expressed by the following equation:
This polynomial has roots 
such that 
, given by the following formulas:
The signal of 
determines how many real roots an equation has:
: Two real and different solutions
: One real solution
: No real solutions
In this problem, we have the following second order polynomial:
.
This means that 
It has one solution if
We can simplify by 8
The solution is:
or
So, if or , there is only one solution to the given quadratic equation.
Since the x value can be changed to anything other than 4 (because then you would be dividing by 0 in x-4), the answer is: All real numbers except 4.
Inverse Property, I am pretty sure. Not sure though.
Let i = sqrt(-1) which is the conventional notation to set up an imaginary number
The idea is to break up the radicand, aka stuff under the square root, to simplify
sqrt(-8) = sqrt(-1*4*2)
sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)
sqrt(-8) = i*2*sqrt(2)
sqrt(-8) = 2i*sqrt(2)
<h3>Answer is choice A</h3>
