Answer:
We have the equation
we leave the terms with x on the left side of the equation and the independent terms on the right side.
resolving for x we have that
Since we need that the equation doesn't have solution, then it is necessary that the denominator of x be 0 and this occur when 
Then, for 
the equation hasn't solution
P(x)=2x 4 −x 3 +2x 2 −6P, left parenthesis, x, right parenthesis, equals, 2, x, start superscript, 4, end superscript, minus, x,
Tresset [83]
Answer:
P = -x^3 +12 / x+6
Step-by-step explanation:
Let's solve for p.
px=(2)(4)−x3+(2)(2)−6p
Step 1: Add 6p to both sides.
px+6p=−x3−6p+12+6p
px+6p=−x3+12
Step 2: Factor out variable p.
p(x+6)=−x3+12
Step 3: Divide both sides by x+6.p(x+6)
x+6
=
−x3+12
x+6
p=
−x3+12
x+6
Make an equation system based on the problem
eg. a is the first number and b is the seond number
An equation for "<span>The sum of two numbers is 53" is
</span>⇒ a + b = 53
An equation for "<span>twice the first number minus three times the second number is 26"
</span>⇒ 2a - 3b = 26
<span>
Solve the equations by elimination and subtitution method
Eliminate a to find the value of b
a + b = 53 (multiplied by 2)
2a - 3b = 26
--------------------------------------
2a + 2b = 106
2a - 3b = 26
------------------- - (substract)
5b = 80
b = 80/5
b = 16
Subtitute the value of b to one of the equations
a + b = 53
a + 16 = 53
a = 53 - 16
a = 37
The numbers are 16 and 37</span>
-2,-7 because you go the same ammount in the opposite direction
Answer:
f = 1
Step-by-step explanation:
Use the method of cross- multiplication
= 
⇒ ad = bc, thus
20f = 5(f + 3) ← distribute
20f = 5f + 15 ( subtract 5f from both sides )
15f = 15 ( divide both sides by 15 )
f = 1
