Is there a tip for finding out calendar days in different months? Say, for ex : If 30th of April is Wednesday, what does 30th of
1 answer:
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The graph looks like this, on the enclosed pic:
One feature is that it's periodic and torn (has cut-off points), meaning the domain is the same as in case of tan(x): x€R and x =/= π/2+πn.
The range equals the range of arcsin(x): -π/2<=y<=π/2 OR y€[-π/2;π/2]
Hope could understand and if it helped! :)
One feature is that it's periodic and torn (has cut-off points), meaning the domain is the same as in case of tan(x): x€R and x =/= π/2+πn.
The range equals the range of arcsin(x): -π/2<=y<=π/2 OR y€[-π/2;π/2]
Hope could understand and if it helped! :)
Answer:
25
Step-by-step explanation:
We require to solve for n, hence
n(n + 1) = 325
multiply both sides by 2 to eliminate the fraction
n(n + 1) = 650
n² + n = 650
subtract 650 from both sides to have equation in standard form
n² + n - 650 = 0 ← in standard form
(n + 26)(n - 25) = 0 ← in factored form
equate each factor to zero and solve for n
n + 26 = 0 ⇒ n = - 26
n - 25 = 0 ⇒ n = 25
however, n > 0 ⇒ n = 25
Answer:
5 hours
Step-by-step explanation:
given :
Distance between the cities = 540 miles
Speed of motorcycle =48 mph
TO CALCULATE THE TIME TAKEN BY MOTORCYCLE TO COVER THE TOTAL DISTANCE WE USE THE FORMULA :
By putting given values in the formula we get :
= 11.25 hours
Now, We are given that for a car to cover the same distance it takes 2.25 hours less than the time taken by motorcycle
⇒ 11.25 hours - 2.25 hours
⇒ 9 hours
Thus , Time taken by car to cover the same distance is 9 hours .
Now to calculate speed of car by using formula:
= 60 mph
Let t be the time taken to meet if they start moving towards each other.
So distance covered by motorcycle in t hours is
speed\times time
= 48t miles
Distance covered by car in t hours is
speed\times time
= 60t miles
⇒ 60t + 48t =540
⇒ 108t = 540
⇒ t= 5 hours
Therefore, time taken to meet if they start moving towards each other is 5 hours.
