Answer:
<u>b(n) = -11 + (n-1)*8</u>
<u></u>
Step-by-step explanation:
Let n be the sequence number, with n=1 the first number b(1) -11
The sequence changes by +8 each step.
<u><em>b(1)</em></u><em> -11</em> + 8 = -3
<u><em>b(2)</em></u><em> -3</em> + 8 = 5
<u><em>b(3)</em></u> <em> 5 </em> + 8 = 13
<u><em>b(4)</em></u><em> </em> <em>13</em>
b(1) = -11
b(2) = -3. or b(1) + 1*8
b(3) = 5, or b(1) + 2*8
b(4) = 13, or b(1) + 3*8
We note that each step adds a multiple of 8 to the initial value of -11. This can be stated as (n-1)*8
The formula for this sequence would be b(n) = b(1) + (n-1)*8
<u>b(n) = -11 + (n-1)*8</u>
Check: Does n=3 return the value of 5?
b(n) = -11 + (n-1)*8
b(3) = -11 + ((3)-1)*8
b(3) = -11 + (2)*8
b(3) = -11 + 16
b(3) = 5 <u><em>YES</em></u>
