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igomit [66]
3 years ago
5

What do you get when you evaluate (-1) 50?

Mathematics
2 answers:
RoseWind [281]3 years ago
3 0

Answer:--50

Step-by-step explanation:

Ivanshal [37]3 years ago
3 0
Answer: -50

This equation is asking you to multiply 50 by -1. When a number is in parentheses alone next to another number, the equation is usually asking for multiplication.

When a number is multiplied one, the value of the number remains the same. Since this is -1, however, the value will become -50.

This is your answer! Hope this helps comment below for more questions :)
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Suppose a study estimated that 62% of the residents of a community (with an
kati45 [8]

Answer:

D. 55%

Step-by-step explanation:

The error range ± 9% means that the range is 9% below 62% or 9% above 62%.

The range is:

(62% - 9%) to (62% + 9%)

53% to 71%.

The only answer between 53% and 71% is 55%.

Answers A, B, C are all greater than 71%.

5 0
3 years ago
2/7 divided by 1/2 as a mixed number
Readme [11.4K]

Answer:

4/7

Step-by-step explanation:

2/7 ÷1/2=2/7 × 2 = 4/7

Hope this helps :D

8 0
3 years ago
Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.
Ann [662]
Note that if {x_2}'=x_1, then {x_2}''={x_1}', and so we can collapse the system of ODEs into a linear ODE:

{x_2}''=3{x_2}'-x_2+e^t
{x_2}''-3{x_2}'+x_2=e^t

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0

so that the characteristic solution is

{x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}

Now let's suppose the particular solution is {x_2}_p=ae^t. Then

{x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t

and so

ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1

Thus the general solution for x_2 is

x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t

and you can find the solution x_1 by simply differentiating x_2.
7 0
3 years ago
Please help me up there
Anettt [7]
The answer is 38,400

The scale is 1:40 so the side that is 4 in becomes 160 and the side that is 6 in becomes 240
Multiply 160 and 240 and that is the area of the room

Hope this helps
6 0
3 years ago
I need help with this Factoring Quadratics question.Can someone help me?
antoniya [11.8K]

If you mean "factor over the rational numbers", then this cannot be factored.

Here's why:

The given expression is in the form ax^2+bx+c. We have

a = 3

b = 19

c = 15

Computing the discriminant gives us

d = b^2 - 4ac

d = 19^2 - 4*3*15

d = 181

Note how this discriminant d value is not a perfect square

This directly leads to the original expression not factorable

We can say that the quadratic is prime

If you were to use the quadratic formula, then you should find that the equation 3x^2+19x+15 = 0 leads to two different roots such that each root is not a rational number. This is another path to show that the original quadratic cannot be factored over the rational numbers.

7 0
3 years ago
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