Six is greater than or equal to the quotient of a number y and 2.5

Michael and Daniel are on a team together. Michael scores 5 points on his turn, but Daniel loses 5 points on his turn.

Tomtit [17]

Answer: They don’t score any points, because since micheal scored 5 points, but Daniel lost those 5 points. They still have 0

Step-by-step explanation:

4 0

2 years ago

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What is the probality that there will be 5 Saturday's in the month of May

goblinko [34]

Answer:

4/31

Step-by-step explanation:

Im.not too sure about the answer but i think its that

3 0

2 years ago

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The number of people arriving at a ballpark is random, with a Poisson distributed arrival. If the mean number of arrivals is 10,

Stella [2.4K]

Answer:

a) 3.47% probability that there will be exactly 15 arrivals.

b) 58.31% probability that there are no more than 10 arrivals.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

If the mean number of arrivals is 10

This means that $\mu = 10$

(a) that there will be exactly 15 arrivals?

This is P(X = 15). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 15) = \frac{e^{-10}*(10)^{15}}{(15)!} = 0.0347$

3.47% probability that there will be exactly 15 arrivals.

(b) no more than 10 arrivals?

This is $P(X \leq 10)$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-10}*(10)^{0}}{(0)!} = 0.000045$

$P(X = 1) = \frac{e^{-10}*(10)^{1}}{(1)!} = 0.00045$

$P(X = 2) = \frac{e^{-10}*(10)^{2}}{(2)!} = 0.0023$

$P(X = 3) = \frac{e^{-10}*(10)^{3}}{(3)!} = 0.0076$

$P(X = 4) = \frac{e^{-10}*(10)^{4}}{(4)!} = 0.0189$

$P(X = 5) = \frac{e^{-10}*(10)^{5}}{(5)!} = 0.0378$

$P(X = 6) = \frac{e^{-10}*(10)^{6}}{(6)!} = 0.0631$

$P(X = 7) = \frac{e^{-10}*(10)^{7}}{(7)!} = 0.0901$

$P(X = 8) = \frac{e^{-10}*(10)^{8}}{(8)!} = 0.1126$

$P(X = 9) = \frac{e^{-10}*(10)^{9}}{(9)!} = 0.1251$

$P(X = 10) = \frac{e^{-10}*(10)^{10}}{(10)!} = 0.1251$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.000045 + 0.00045 + 0.0023 + 0.0076 + 0.0189 + 0.0378 + 0.0631 + 0.0901 + 0.1126 + 0.1251 + 0.1251 = 0.5831$

58.31% probability that there are no more than 10 arrivals.

8 0

2 years ago

When Mr. P. drinks an 8-ounce glass of cola, how many teaspoons of sugar is he consuming if one teaspoon of sugar provides 4 gra

natta225 [31]

The number of teaspoons of sugar that Mr. P. consumes is = 56.7 teaspoons.

<h3>Calculation of total sugar quantity</h3>

The total amount of cola taken is 8-ounce

To covert ounce to grams , the following is carried out;

1 ounce =28.35g

8 ounce = X

Xg = 8 × 28.35

X = 226.8g

But one teaspoon = 4 grams

X teaspoon = 226.8g

cross multiply to solve for x

X = 226.8g/ 4

X = 56.7 teaspoons

Therefore, the number of teaspoons of sugar that Mr. P. consumes is = 56.7 teaspoons.

Learn more about multiplication here:

brainly.com/question/10873737

4 0

1 year ago

A square pyramid has a base edge of 15 inches. The volume of the pyramid is 960 cubic inches. What is the height of the pyramid,

gizmo_the_mogwai [7]

Answer: h=12.8in

a Base edge 15 in

V Volume 960 in³

Using the formula

V=a2h

3

Solving for h

h=3V

a2=3·960

152=12.8in

Step-by-step explanation:

8 0

2 years ago