From the diagram, we are given that triangle ABC and triangle ADC shares the same side AC, so it means both triangles have one congruent side.
We are also given that angle BAC and angle DAC are equal.
If we want to prove the triangles congruent using Angle-Angle-Side congruent postulate, we need to see one angle in each triangle that is congruent. We will need the information either: ACB = ACD or ABC = ADC
Correct answer: fourth option
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Answer:
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Step-by-step explanation:
Remember that the Intermediate Value Theorem (IVT) states that if f is a continuous function on [a,b] and f(a)<M<f(b), there exists some c∈[a,b] such that f(c)=M.
Now, to apply the theorem, we have that f(0)=0²+0-1=-1, f(5)=5²+5-1=29, then f(0)=-1<11<29=f(5). Additionally, f is continous since it is a polynomial. Then the IVT applies, and such c exists.
To find, c, solve the quadratic equation f(c)=11. This equation is c²+c-1=11. Rearranging, c²+c-12=0. Factor the expression to get (c+4)(c-3)=0. Then c=-4 or c=3. -4 is not in the interval, then we take c=3. Indeed, f(3)=3²+3-1=9+3-1=11.
Answer:
d
Step-by-step explanation:
Answer:
thirty thousand, six hundred and eighty-two!
Step-by-step explanation:
