Using a calculator: cos 70 deg = 0.342. Note: it sounds as tho' you were given several answer options. Where are they?
A = -16 b = 0 c = 541
Use the quadratic formula which is
x = [-b +- sq root (b^2 -4*a*c)] / 2*a
x = [-0 +-sq root (0 -4*-16*541)] / 2 * -16
x = + - sq root (0 -4*-16*541) / -32
x = + - sq root (34,624) / -32
x = + - 186.075 / -32
x1 = 186.075 / -32 =
<span>
<span>
<span>
-5.81484375
</span>
</span>
</span>
x2 = -186.075 / -32 =
<span>
<span>
<span>
5.81484375
</span>
</span>
</span>
Because ABCD is a rhombus, ΔABC ~ ΔADC.
The length of AC = 4 (the base of ΔABC.
The height of ΔABC = 7 - 1 = 6
The area of ΔABC is
(1/2)*4*6 = 12
Therefore the area of ABCD = 2*12 = 24
Answer: 24