Answer:
your answer is -5,-10
Step-by-step explanation:
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I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169
with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0
insert into I:
12x=0
x=0
-> only intersection is at (0,0) = option B
Answer:
Step-by-step
The sum must be greater than 1 because
1/2 + 1/2= 2/2 or 1
ex
3/4 + 8/4= 11/4
9/16+15/16=24/16
8/8+9/8=17/8
The greatest common factor is the biggest number taken from the values.
Q1. The answer is <span>A. 5y^6
</span>

Since

, then

Back to our expression:

The greatest common factor is thus

Q2. The answer is <span>D. 12xy^2
</span>

We will use the rule

to factorise the exponents:

The greatest common factor is thus
Answer:
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Step-by-step explanation:
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