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NeX [460]
3 years ago
8

Chandra uses 1/4 ounce of fish food to feed 5 goldfish. What is the unit rate in ounces of fish food per goldfish?

Mathematics
1 answer:
Svetllana [295]3 years ago
3 0

Answer:

1/20

Step-by-step explanation:

You might be interested in
Use the substitution method to solve the system of equations. Choose the
Hatshy [7]

Answer:

(3, 2) is the ordered pair for the given system of equations.

Step-by-step explanation:

Given:

2 x+ y = 8.......................(i)

y = - x + 5........................(ii)

<u>Put y = - x + 5 in equation (i)-</u>

<em>2 x + ( - x+ 5) = 8</em>

<em>2 x - x + 5 = 8</em>

<em>x = 8 - 5</em>

<em>x = 3</em>

<u>Now put x = 3 in equation (ii)-</u>

<em>y = - 3 + 5</em>

<em>y = 2</em>

Hence the (3, 2) is the correct ordered pair.

4 0
3 years ago
In testing the lethal concentration of a chemical found in polluted water. it is found that a certain concentration will kill 20
sasho [114]

Answer:

a) 0.1091

b) 0.9994

c) 0.5886

Step-by-step explanation:

X = the number of fish out of 20 that die after 24 hours

x = 0, 1, 2, . . . , 20

X~ Binomial (n= 20, p =0.20)

P(14 survive) = P(X = 6)

= nC_r p^r q^{n-r}= 20C_6 0.2^6\times0.8^{14}=0.1091

Similarly we can find out

P(at least 10 survive) = P( X <= 10 ) = (Using technology) = 0.9994

P(at most 16 will survive) = P(X <= 16) = (Using technology) = 0.5886

7 0
3 years ago
A piece of wire is 72cm long. Is used to form 2 identical squares. What is the length of each each side of squares?
Sedbober [7]

Answer:

the length of each side of the square are 6 cm

4 0
3 years ago
Read 2 more answers
if a pair of standard dice are rolled what is the probability that one die shows a six but not both of them. reduced fraction an
Novay_Z [31]

Answer:

P=\frac{5}{18}

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.  

The size of the sample space is the total number of possible outcomes  

The event space is the number of outcomes in the event you are interested in.  

so  

Let

x------> size of the event space

y-----> size of the sample space  

if a die is rolled the sample space is

\{1,2,3,4,5,6\}

if two dice rolled the sample space is

\{1,2,3,4,5,6\}*\{1,2,3,4,5,6\}

so

The possible pairs are

y=6*6=36

The size of the event space x is

\{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)\}

x=10

P=\frac{x}{y}

substitute

P=\frac{10}{36}

Simplify

P=\frac{5}{18}

6 0
3 years ago
53 3/4 + 12 2/3. can someone please help me
Mumz [18]

Answer:

66 5/12

Step-by-step explanation:

53 3/4 + 12 2/3 =

53 9/12 + 12 8/12 =

65 17/12 =

66 5/12

5 0
3 years ago
Read 2 more answers
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