60 ft = 20 yds
Hope this helped!
Based on the information given, the computation shows that the distance between them is 2.47 miles.
<h3>
Solving the distance.</h3>
Since one has bearing 41°45', this will be: = 41° + (45/60) = 41° + 0.75 = 41.75°.
The other has bearing 59°13'. This will be:
= 59° + (13/60) = 59° + 0.22 = 59.22°.
The difference of the angles will be:
= 59.22° - 41.75°
= 17.47°
Let the distance between them be represented by c. Therefore, we'll use cosine law to solve the question. This will be:
c² = a² + b² - 2ab cos 17.47°
c² = 20² + 20² - (2 × 20 × 20 × 0.19)
c² = 6.07459
c = 2.47
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The zeroes of the function will be equal to ( 7, -6 ).
<h3>
What is a quadratic equation?</h3>
It is a polynomial with a degree of 2 or the maximum power of the variable is 2 in quadratic equations. It has two solutions as its maximum power is 2.
Given function:-
As we can see that the quadratic equation in the factorized form is ( x - 7 ) ( x+ 6 ) so we will equate each factor to zero.
( x- 7 ) = 0
x = 7
( x+ 6 ) = 0
x = -6
Therefore zeroes of the function will be equal to ( 7, -6 ).
To know more about quadratic equations follow
brainly.com/question/1214333
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Answer:
The Answer is C
Step-by-step explanation:
