fg^3 / g^3f = 1
f^4 / f*f*f*f = f^4 / f^4 = 1
f^2g^3 / f^3g^2 = g/f
f*f/f^2 = f^2 / f^2 = 1
Answer:
f^2g^3 / f^3g^2
The correct answer is
the flagpole is <span>
33 feet high</span>.
Explanation:
Please refer to the attached picture.
We know:
CD = 40 feet
AC = 5 feet
∠BDC = α = 35°
Using trigonometry, we know that the definition of the tangent of an angle is the ratio between the opposite side and the adjacent side, therefore:
tan α = BC / CD
Solving for BC:
BC = CD · <span>tan α
= 40 </span>· tan (35)
= 28 feet
In order to find the height of the flagpole, we need to add the distance of the clinometer from the ground:
AB = BC + AC
= 28 + 5
= 33
Hence, the flagpole is
33 feet high.
For question a) you can do 2 x 7 sine their are 7 days in a week 2 x 7 = 19 so by the end of each week Carmen has $19. in 10 weeks she will have $20 dollars. if in 10 weeks she has $20 wait if it is time two there can't be 35 try 17 cause that's closes so in 17 she will have $36. Same thing Lilly starts with $10 each week she gets $1 a week so 1 x 7 = 7 and since she started with $ 10 she has $17 Lilly must earn 19 dollars to be equal with Carmen. Hope this helps
Answer:
<u>you type </u><u>75</u><u> words per minute.</u>
Step-by-step explanation:
since there are 60 minutes in an hour, simply divide 4,500 by 60 to get 75. i hope this helps you! good luck and have a great day. :)
Not really sure what you are looking for, but this is how to solve equations such as these.
Let:
x = number of pounds of granola
y = numer of pounds of walnuts
The equation he can use to compute the total cost would be:
$2.00x + $6.00y = $12.00
We know that he bought 3 pounds of granola, so we plug in that for the x value:
$2.00(3) + $6.00y = $12.00
$6.00 + $6.00y = $12.00
To isolate the unknown value which is y, we first need to subtract $6.00 from both sides of the equation:
$6.00 + $6.00y - $6.00 = $12.00 - $6.00
$6.00y = $6.00
Then we divide both sides by $6.00:
$6.00y/$6.00 = $6.00/$6.00
y = 1
So the number of bags of walnuts he can buy is 1 bag.