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Zina [86]
2 years ago
15

Solve for h h - 3h - 8 = 14 H=?

Mathematics
2 answers:
sweet [91]2 years ago
8 0

The initial step that must be taken before solving almost any problem is to understand what the problem is asking for us to do and what is provided to us to complete that goal.  Looking at the problem statement, we can see that we are being requested to solve for h and we are provided an expression to do so.  Let's begin solving the expression by combining like terms.

<u>Combine like terms</u>

  • h - 3h - 8 = 14
  • (h - 3h) - 8 = 14
  • (- 2h) - 8 = 14

Just a quick explanation on what combine like terms means, it basically just means to combine the coefficients of the numbers associated with the same variables.  Like in this example we can combine h and -3h because they have have the variable h associated with them.

<u>Add 8 to both sides</u>

  • (- 2h) - 8 = 14
  • (- 2h) - 8+ 8 = 14 + 8
  • - 2h= 22

<u>Divide both sides by -2</u>

  • - 2h= 22
  • \frac{- 2h}{-2}= \frac{22}{-2}
  • h= \frac{22}{-2}

<u>Simplify the expression</u>

  • h= - \frac{22/2}{2/2}
  • h= - \frac{11}{1}
  • h= - 11

Therefore, after completing the steps above we were able to determine that the value of h is equal to -11.

Luba_88 [7]2 years ago
3 0

Answer:

-22

Step-by-step explanation:

h-3h-8=14

-2h=14+8

-2h=22

h=-11

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Step-by-step explanation:

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\huge\text{Hey there!}

\mathsf{-\dfrac{c}{2}+43=50}

\large\text{SUBTRACT 43 to BOTH SIDES}

\mathsf{-\dfrac{c}{2}+43-43=50-43}

\large\textsf{CANCEL out: 43 - 43 because that gives you 0}

\large\textsf{KEEP: 50 - 43 because it helps solve for the c-value}

\mathsf{50 - 43 = \bf 7}

\large\text{NEW EQUATION: }\mathsf{-\dfrac{c}{2}=7}

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\large\textsf{CANCEL out: your RIGHT SIDE of the equation because that gives}\\\large\textsf{you 1}

\large\textsf{KEEP: }\mathsf{\dfrac{2}{-1}\times7}\large\textsf{ because that helps solve for the c-value}

\uparrow\large\text{SIMPLIFY THE EQUATION ABOVE \& YOU HAVE YOUR}\\\large\text{C-VALUE}\uparrow

\boxed{\boxed{\large\text{ANSWER: \huge\bf  c = -14}}}\huge\checkmark

\large\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

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