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1 year ago

13

in a survey of 200 students 120 were taking mathematics and 50 were taking speech what is the least number of students who could

have been taking both courses.

1 answer:

lara [203]1 year ago

6 0

Answer:30
200-120-50=30

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Suling bought 3meters of ribbons she used 5/6meter to make a bow find the length of the ribbon left

Ostrovityanka [42]

Subtract the portion used from the whole.

= 3 m - 5/6m
must have common denominators
= (3*6)/(1*6) - 5/6
= 18/6 - 5/6
= 13/6 m
= 2 1/6 m

ANSWER: 2 1/6 meters left

Hope this helps! :)

5 0

3 years ago

VXYZ is a kite. What is the length of XY?

olga nikolaevna [1]

Answer:

$5x - 6 = 3x + 4 \\ 5x - 3x = 4 + 6 \\ 2x = 10 \\ x = 10 \div2 \\ x = 5 \\ length \: of \: xy = 3 \times 5 + 4 \\ = 15 + 4 \\ = 19$

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2 years ago

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What is the value of x in the solution to this system of equations?

liberstina [14]

Answer:

x = 11

Step-by-step explanation:

Given the expression;

5x+2y=67 ...1

x=3y−7 ....2

Substitute 2 into 1

5(3y-7)+2y = 67

15y - 35 + 2y = 67

17y = 67+35

17y = 102

y = 102/17

y =6

Recall that x = 3y - 7

x = 3(6) - 7

x = 18 - 7

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3 years ago

A right pyramid with a regular hexagon base has a height of 3 units If a side of the hexagon is 6 units long, then the apothem i

Setler79 [48]

Answer:

Part a) The slant height is $3\sqrt{2}\ units$

Part b) The lateral area is equal to $54\sqrt{2}\ units^{2}$

Step-by-step explanation:

we know that

The lateral area of a right pyramid with a regular hexagon base is equal to the area of its six triangular faces

so

$LA=6[\frac{1}{2}(b)(l)]$

where

b is the length side of the hexagon

l is the slant height of the pyramid

Part a) Find the slant height l

Applying the Pythagoras Theorem

$l^{2}=h^{2} +a^{2}$

where

h is the height of the pyramid

a is the apothem

we have

$h=3\ units$

$a=3\ units$

substitute

$l^{2}=3^{2} +3^{2}$

$l^{2}=18$

$l=3\sqrt{2}\ units$

Part b) Find the lateral area

$LA=6[\frac{1}{2}(b)(l)]$

we have

$b=6\ units$

$l=3\sqrt{2}\ units$

substitute the values

$LA=6[\frac{1}{2}(6)(3\sqrt{2})]=54\sqrt{2}\ units^{2}$

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3 years ago

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I rly need help with #2-4 and #8-9 PLZZ

castortr0y [4]

Answer:

2. sin=12\15 cos=9/15 tg=12/9

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3 years ago