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andrew11 [14]
2 years ago
13

in a survey of 200 students 120 were taking mathematics and 50 were taking speech what is the least number of students who could

have been taking both courses.
Mathematics
1 answer:
lara [203]2 years ago
6 0
Answer:30
200-120-50=30
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Find the value of x.
vredina [299]

Answer:

50

Step-by-step explanation:

8 0
3 years ago
Approximately 40% of the calls to an airline reservation phone line result in a reservation being made. (round to three decimal
IRISSAK [1]

Answer:

The probability that none of the 10 calls result in a reservation is 0.60%.  In turn, the probability that at least one call results in a reservation being made is 99.40%.

Step-by-step explanation:

Since approximately 40% of the calls to an airline reservation phone line result in a reservation being made, supposing an operator handles 10 calls, to determine what is the probability that none of the 10 calls result in a reservation, and what is the probability that at least one call results in a reservation being made, the following calculations must be performed:

0.6 ^ 10 = X

0.006 = X

0.006 x 100 = 0.60%

Therefore, the probability that none of the 10 calls result in a reservation is 0.60%.

100 - 0.60 = 99.40

In turn, the probability that at least one call results in a reservation being made is 99.40%.

3 0
2 years ago
Please answer this ??
Vadim26 [7]
The answer is 24.5. Just plug the numbers in
7 0
3 years ago
Which expression is equivalent to:<br> 5x2 - 10x - 7+ 5x2 + 8?
LenaWriter [7]

Answer:

Step-by-step explanation:

5x² -  10x - 7 + 5x² + 8 = 5x² + 5x² -10x - 7 + 8

                                    = 10x² - 10x + 1

Bring like terms together and add/ subtract the like terms

4 0
3 years ago
A manufacturer of computer printers purchases plastic ink cartridges from a vendor. When a large shipment is received, a random
g100num [7]

Answer:

97.4% probability

Step-by-step explanation:

Since there is only two possible outcome of inspecting the catridge : either defective or not, we can solve the problem using the binomial probability distribution (approximated to normal).

To approximate the binomial probability to normal, we find the expected value and the standard deviation of the probability of exactly x sucesses on n repeated trials with p probability

Expected values E(X) = np

Standard deviation √V(X) = √np(1-p)

using the z-score formula (X - μ)/σ, we can solve normally distributed problem.

Where μ is the mean and σ is the standard deviation. The Z-score is is the measure of how much a sample is from the mean. The p-value associated with this z-score which is the probability that the value of the measure is smaller than X can be checked on the z-score table.

FOR THIS QUESTION,

a random sample of 200 cartridges is selected

n = 200

Therefore If there are more than 0.02 × 200 = 4 defective, the sample will be returned.

To determine the approximate probability that a shipment will be returned if the true proportion of defective cartridges in the shipment is 0.05

μ = E(X)

= 0.05 × 200 = 10

σ = √V(X) = √np(1-p)

= √200 × 0.05 × 0.95

= 3.08

This probability is 1 subtracted by the pvalue of Z when X =4

Z = (X - μ)/σ

Z= (4 - 10)/3.08

Z = -1.95

Z = -1.95 has a P-value of 0.026 (on the z-score table)

This means that there is a 1 - 0.026 = 0.974

= 97.4% probability that a shipment will be returned if the true proportion of defective cartridges in the shipment is 0.05.

6 0
3 years ago
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