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3 years ago

Here goes problem 4 i need help

Mathematics

2 answers:

hichkok12 [17]3 years ago

3 0

The only tricky thing about this problem is that you have to know
the formula for the area of a triangle. The formula is

   Area of a triangle = (1/2) times (length of the base) times (the height) .

In this picture, 'x' is the base, and 'h' is the height. That's all you need
in order to find the area. You don't need to know 'y' or 'z' at all.

   Area = (1/2) x (base) x (height)

   = (1/2) x (13) x (6)

   = (1/2) x ( 78 ) = <em>39 inches²

</em>

SVETLANKA909090 [29]3 years ago

3 0

Multiply 13*6=78 then multiply with .5 (78*.5=39)

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Whitepunk [10]

Answer: it is 24 UWU

Step-by-step explanation:

4 0

3 years ago

If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf

jonny [76]

With the curve $C$ parameterized by

$C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k$

with $0\le t\le\dfrac\pi2$ , and given the vector field

$\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k$

the work done by $\mathbf f$ on a particle moving on along $C$ is given by the line integral

$\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt$

where

$\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt$

The integral is then

$\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt$
$=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t$
$=269$

6 0

3 years ago

Solve the equation.<br> 6 = 3s <br> what is s?????

swat32

The variable s I equal to the number 2

6 0

2 years ago

Read 2 more answers

Mei and Alberto are selling cookie dough. Mei sold 11 packages of chocolate chip and 12 packages of gingerbread for a total of $

ycow [4]

Answer:

The price of a package of chocolate chip is $13.25

The price of a package of gingerbread is $17.18

Step-by-step explanation:

11x + 12y = 352

10x +8y = 270

Let "x" be the price of a package of chocolate chip.

Let "y" be the price of a package of gingerbread.

11x + 12y = 352(Multiply the 1st row by 10)

10x +8y = 270 (Multiply the 2nd row by 11)

-------------------

110x + 120y = 3520

110x +88y = 2970

--------------------------

3y = 550

y =550/3

y = 17.1875

The price of a package of gingerbread "y" is $17.18

Let's pick the first equation "110x + 120y = 3520"

110x + 120y = 3520

110x+ 120(17.1875)= 3520

110x+2062.5=3520

110x=3520−2062.5

110x=1457.5

x= 1457.5/110

x=13.25

The price of a package of chocolate chip is $13.25

6 0

2 years ago

1. Find the mean for 2, 5, 9, 4

Reil [10]

Answer:

Answer 1. 5 Answer 2. 60 Answer 3. 37

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers