Here goes problem 4 i need help

Mathematics

2 answers:

hichkok12 [17]3 years ago

3 0

The only tricky thing about this problem is that you have to know
the formula for the area of a triangle. The formula is

 Area of a triangle = (1/2) times (length of the base) times (the height) .

In this picture, 'x' is the base, and 'h' is the height. That's all you need
in order to find the area. You don't need to know 'y' or 'z' at all.

 Area = (1/2) x (base) x (height)

 = (1/2) x (13) x (6)

 = (1/2) x ( 78 ) = 39 inches²

SVETLANKA909090 [29]3 years ago

3 0

Multiply 13*6=78 then multiply with .5 (78*.5=39)

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1. Write the equation in standard form. Identify the important features of the graph:

NeTakaya

Answer:

(x-4.5)^2 +(y +5)^2 = 30.25
x = (1/8)y^2 +(1/2)y +(1/2)
y^2/36 -x^2/64 = 1
x^2/16 +y^2/25 = 1

Step-by-step explanation:

1. Complete the square for both x and y by adding a constant equal to the square of half the linear term coefficient. Subtract 15, and rearrange to standard form.

(x^2 -9x +4.5^2) +(y^2 +10y +5^2) = 4.5^2 +5^2 -15

(x -4.5)^2 +(y +5)^2 = 30.25 . . . . . write in standard form

Important features: center = (4.5, -5); radius = 5.5.

2. To put this in the form x=f(y), we need to add 8x, then divide by 8.

x = (1/8)y^2 +(1/2)y +(1/2)

Important features: vertex = (0, -2); focus = (2, -2); horizontal compression factor = 1/8.

3. We want y^2/a^2 -x^2/b^2 = 1 with a=36 and b=(36/(3/4)^2) = 64:

y^2/36 -x^2/64 = 1

4. In the form below, "a" is the semi-axis in the x-direction. Here, that is 8/2 = 4. "b" is the semi-axis in the y-direction, which is 5 in this case. We want x^2/a^2 +y^2/b^2 = 1 with a=4 and b=5.

x^2/16 +b^2/25 = 1

_____

The first attachment shows the circle and parabola; the second shows the hyperbola and ellipse.