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Sunny_sXe [5.5K]
2 years ago
6

Tom works at an aquarium shop on Saturdays. One Saturday, when Tom gets to work, he is asked to clean a 180-gallon reef tank. Hi

s first job is to drain the tank. He puts a hose into the tank and starts a siphon. Tom wonders if the tank will finish draining before he leaves work. He charts the amount of water remaining in the tank over time as shown in the table below.
Mathematics
1 answer:
vlada-n [284]2 years ago
8 0

Please find the question attached below.

The equation that models the decrease in water (in gallons) of the fish tank over time (in hours) is y = - 20x + 180.

We know that a linear equation with one variable is one that contains just one variable.

Here we have to find the appropriate equation that models the given chart.

For option A. :

y = - 40x + 140

At x = 2, y = - 40*2 + 140 = - 80 + 140 = 60 =/ 140

So this option is incorrect.

For option B.:

y = - 40x + 180

At x = 2, y = - 40*2 + 180 = - 80 + 180 = 100 =/ 140

So this option is incorrect.

For option C.:

y = - 20x + 140

At x = 2, y = - 20*2 + 140 = - 40 + 140 = 100 =/ 140

So this option is incorrect.

For option D.:

y = - 20x + 180

At x = 2, y = - 20*2 + 180 = - 40 + 180 = 140

So this option is correct.

Therefore, the equation that models the decrease in water (in gallons) of the fish tank over time (in hours) is y = - 20x + 180. So, the last option is correct.

Learn more about linear equations here -

brainly.com/question/26950036

#SPJ10

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Which of the following rational functions is graphed below?​
vampirchik [111]

Answer:

The correct option is D.

i.e.

f\left(x\right)=\frac{1}{x\left(x+4\right)} is the correct option.

The correct graph is shown in attached figure.

Step-by-step explanation:

Considering the function

f\left(x\right)=\frac{1}{x\left(x+4\right)}

\mathrm{Domain\:of\:}\:\frac{1}{x\left(x+4\right)}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x

\mathrm{Range\:of\:}\frac{1}{x\left(x+4\right)}:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:-\frac{1}{4}\quad \mathrm{or}\quad \:f\left(x\right)>0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-\frac{1}{4}]\cup \left(0,\:\infty \:\right)\end{bmatrix}

\mathrm{Axis\:interception\:points\:of}\:\frac{1}{x\left(x+4\right)}:\quad \mathrm{None}

\mathrm{Extreme\:Points\:of}\:\frac{1}{x\left(x+4\right)}:\quad \mathrm{Maximum}\left(-2,\:-\frac{1}{4}\right)

So, the correct graph is shown in attached figure.

Therefore, the correct option is D.

i.e.

f\left(x\right)=\frac{1}{x\left(x+4\right)} is the correct option.

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