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krok68 [10]
3 years ago
11

Identify the transformation that maps the figure onto itself.

Mathematics
2 answers:
jasenka [17]3 years ago
7 0
The answer for this letter is c
11Alexandr11 [23.1K]3 years ago
3 0

Answer:

The correct option is C.

Step-by-step explanation:

From the given figure it is clear that the vertices of the parallelogram are (0,0), (0,-6), (4,-8) and (4,-2).

If a figure rotated 180° about (a,b), then

(x,y)\rightarrow (2a-x,2b-y)

If the figure rotated 180° about (2,-4), then

(x,y)\rightarrow (2(2)-x,2(-4)-y)

(x,y)\rightarrow (4-x,-8-y)

So, the vertices of image after rotated 180° about (2,-4) are

(0,0)\rightarrow (4,-8)

(0,-6)\rightarrow (4,-2)

(4,-8)\rightarrow (0,0)

(4,-2)\rightarrow (0,-6)

The vertices of image are same as vertices of preimage. So, 180° rotation about (2,-4) maps the figure onto itself.

Therefore the correct option is C.

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\dfrac{ \dfrac{x+3}{4x^2-16} }{ \dfrac{2x^2+10x+12}{2x-4} }

-----------------------------------------------------------------------------------
Write the divide fraction horizontally:
-----------------------------------------------------------------------------------

= \dfrac{x+3}{4x^2-16} \div \dfrac{2x^2+10x+12}{2x-4}

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Factorise the numerators and denominators when possible:
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= \dfrac{x+3}{4(x+2)(x-2)} \div \dfrac{ 2(x + 3) (x + 2)}{2(x-2)}

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Convert the divide fraction to multiplication fraction
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= \dfrac{x+3}{4(x+2)(x-2)} \times \dfrac{2(x-2)}{2(x+3)(x+2)}

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Cancel the factors
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= \dfrac{1}{4(x+2)} \times \dfrac{1}{(x+2)}

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Combine to single fraction
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= \dfrac{1}{4(x+2)^2}



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