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viva [34]
3 years ago
15

Write an equation of the line in point slope form: A line that passes through (4,-5) with a slope of -6 (Show Work)

Mathematics
1 answer:
Sladkaya [172]3 years ago
8 0
When u get A screenshot it and do x
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Claire is putting up a fence around her rectangular garden. The length is four less than double the width. The perimeter is 22 f
Doss [256]

Answer:

The dimensions are 6 by 5 feet.

Length = 6 feet.

Width = 5 feet.

Step-by-step explanation:

Let the length = L

Let the width = W

Perimeter of a rectangle = 2L + 2W

Translating the word problem into an algebraic equation, we have;

L = 2W - 4 ........equation 1

22 = 2L + 2W .......equation 2

Substituting the value of "L" into equation 2, we have;

22 = 2(2W - 4) + 2W

22 = 4W - 8 + 2W

22 + 8 = 6W

30 = 6W

W = 30/6

Width, W = 5 feet.

To find the length, L

Substituting the value of "W" into equation 1, we have;

L = 2W - 4

L = 2(5) - 4

L = 10-4

Length, L =6 feet

Therefore, the dimensions of the garden are 6 by 5 feet.

5 0
2 years ago
Given f(x)=-1/7√16-x^2 find f^-1(x)
Vera_Pavlovna [14]

Answer:

f^{-1}(x)=\pm \sqrt{49x^2-16}

Not a function.

Step-by-step explanation:

The given function is;

f(x)=-\frac{1}{7}\sqrt{16-x^2}

Let y=-\frac{1}{7}\sqrt{16-x^2}

Interchange x and y;

x=-\frac{1}{7}\sqrt{16-y^2}

Solve for y;

-7x=\sqrt{16-y^2}

Square both sides

(-7x)^2=(\sqrt{16-y^2})^2

49x^2^2=16-y^2

49x^2^2-16=y^2

y=\pm \sqrt{49x^2-16}

The inverse is

f^{-1}(x)=\pm \sqrt{49x^2-16}

f^{-1}(x)=\pm \sqrt{49x^2-16} is not a function because one x-value maps onto to different y-values.

6 0
3 years ago
0.47=_ hundredths = _tenths and _ hundredths
Gennadij [26K]
7 hundredths 4 tenths
4 0
3 years ago
Read 2 more answers
HELP ASAP with this question.
Soloha48 [4]
The answer is A, 16. Here's some work: 

6x + 2 = 98
6x = 96
x = 16
7 0
3 years ago
Read 2 more answers
HELP IF U CAN! ASAP PLEASE!
lesya692 [45]

Answer:

Just do your best

Step-by-step explanation:

6 0
2 years ago
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