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Alexeev081 [22]
3 years ago
14

Give an example for a pair of alternate interior angles, a pair of corresponding angles, and a pair of alternate exterior angles

,and a pair of alternate interior angles.​

Mathematics
1 answer:
cluponka [151]3 years ago
4 0

Answer:

One way to identify alternate exterior angles is to see that they are the vertical angles of the alternate interior angles.

Step-by-step explanation:

so if I was you I would use that strategy to try to find the pair of the Alternate exterior angles.

so the agles are probably 1 and 7 but i don’t want you to get it wrong so here’s a picture Of an example.

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Select the correct answer.<br><br> Which expression is equivalent to sin^2x-sinx-2/sinx-2?
ladessa [460]

Answer:

A

Step-by-step explanation:

We are given:

\displaystyle \frac{\sin^2(x)-\sin(x)-2}{\sin(x)-2}

To make it simpler and more clear, we can let u = sin(x). So:

\displaystyle \frac{u^2-u-2}{u-2}

Now, it becomes obvious that we can factor, which produces:

\displaystyle =\frac{(u-2)(u+1)}{u-2}

Cancel:

=u+1

And substituting back:

=\sin(x)+1

Hence, our answer is A.

3 0
3 years ago
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Can someone solve this???
nalin [4]

Answer:

1. a)x² + y² = 29  ------------------(1)      

y² - x² = 23 ----------------(2)

y²  = 23 + x²

Using the value of y² in the first equation:

<em>x²  + y²  = 29</em>

<em>x²  + (23 + x²)  = 29</em>

<em>2x²  = 6</em>

<em>x² = 3</em>

x = √3

Using the value of x in equation (2)

<em>y²  - x²  = 23 </em>

<em>y²  - 3 = 23</em>

<em>y²  = 26 </em>

<u>y = √26</u>            <u>and</u>            <u>x = √3</u>

<u></u>

<u>b)</u> ( 1 - 12x) / 3 < 0   =   1-12x < 0  =  x > 1 / 12

(1-x) / 2 ≤ (3-x) 3  =  3 - 3x ≤ 6 - 2x  =   -3 ≤ x

In these 2 equations, the value of x will be the values of x common to both the inequalities

Since the second equation starts at a much lower value than the first equation, and they are both going up, all the values for the first equation will also stand for the second equation

Hence, the value of x for the given system of equations is

x  > 1/12

2.

3x² - 7x  + 2 ≥ 0

3x² -6x -1x  + 2 ≥ 0       (splitting the middle term)

3x(x - 2) -(x - 2) ≥ 0

(3x - 1)(x-2) ≥ 0

(3x-1) ≥ 0         or     (x-2) ≥ 0

x ≥ 1/3       or    x ≥ 2

Written above are the 2 solutions for the given equation

4.

We are given that Sin α = (2√3) / 3  or 2/√3

According to the pythagorean law:

<em>sin²α + cos²α = 1</em>

<em>4 / 3  + cos²α = 1</em>

<em>cos²α = (3-4)/3</em>

<em>cos²α = -1/3</em>

cos α = √(-1/3)      or    i / √3    since √-1 is also known as i

<em>Cosec α = 1/ Sin α</em>

<em>Cosec α = 1 / (2/√3)</em>

Cosec α = √3 / 2

<em>Sec α = 1 / cos α</em>

<em>Sec α = 1 /  √(-1/3)</em>

<em>Sec α = (√3)  / (√-1)</em>

Since (√-1) is also known as i , we can write this as:

Sec α = (√3)  / i

<em>Tan α = Sin α / Cos α</em>

<em>Tan α = (2√3 / 3) / (i / √3)</em>

<em>Tan α = (2√3 * √3) / 3 * i)</em>

Tan α = 2 / i

<em>Cot α = 1/Tan α</em>

<em>Cot α = 1 / (2 / i)</em>

Cot α = i / 2

8 0
3 years ago
If a polynomial has one root in the form a+ vb, it has a second root in the<br> form of a__ vb.
allochka39001 [22]

Answer:

a - vb

Step-by-step explanation:

6 0
3 years ago
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PLEASE HELP thanks -lyssa
Lostsunrise [7]
This answer is 12 
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inysia [295]

the numerators are the top number and the numbers are: 11, 7, 12, and 0

the denominator is the bottom and the numbers are: 12, 512, 10, and 78

hope this helps!

3 0
3 years ago
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