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Vlada [557]
3 years ago
12

Avi's pet hamster Chubby loves to run in his hamster wheel. During one "race", Avi counts 100 rotations of the wheel. She wants

to know how far Chubby ran, so she measures the diameter of the wheel and finds that it is 8 inches. How far did Chubby run? Give your answer in terms of pi. (prize is 99 points)
Mathematics
2 answers:
Fantom [35]3 years ago
5 0
Answer: 800pi inches

=======================================

Explanation:

The formula to find the circumference of a circle is
C = pi*d
where
C = distance around the circle (aka circumference)
pi = 3.14 approximately
d = diameter

We know that the diameter of the wheel is d = 8, so 
C = pi*d
C = pi*8
C = 8pi
is the circumference of the wheel

One full rotation will have the wheel cover a distance of 8pi inches. Imagine that wet paint is on the outer surface of the wheel. If the wheel is rolled out in a straight line, then the wet paint would cover a linear distance of 8pi inches along the flat ground. This is one full rotation, so 100 rotations covers 100*8pi = 800pi inches

Note: if we use pi = 3.14 as the approximation, then the hamster ran approximately 800*pi = 800*3.14 = 2512 inches if the wheel could move
Kay [80]3 years ago
3 0

Answer:

6280

Step-by-step explanation:

It's 6280

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A rectangle has length X +5 and width X +4 if the perimeter of the rectangle is 42 m what are the length and width of the rectan
Maru [420]
The perimeter is 2(length) + 2(width), so 2(x+5) + 2(x+4) = 42 m. In solving for x, you find 6. Plug 6 back into your length and width where x originally was, and you find your length to be 11m, and your width to be 10m. Hope this helps!
6 0
3 years ago
Read 2 more answers
In 1997 there were 31 laptop computers at Grove High School. Starting in 1998 the school bought 20 more laptop computers at the
Kruka [31]

Using the linear equation, T = 20x + 31, the total number of computers at the end of 2005 is: C. 191.

<h3>How to Use a Linear Equation?</h3>

A linear equation is expressed as y = mx + b, where x is a function of y, m is the rate of change and b is the y-intercept or starting value.

In the scenario stated, we are given the linear equation for total number of laptop computers at the school after 1997 as, T = 20x + 31.

Rate of change = 20

y-intercept/starting value = 31

x = 2005 - 1997 = 8

To find the total number of laptop computers at Grove High School at the end of 2005 (T), substitute x = 8 into the equation, T = 20x + 31.

T = 20(8) + 31

T = 160 + 31

T = 191 computers.

Thus, total number of computers at the end of 2005 is: C. 191.

Learn more about linear equation on:

brainly.com/question/15602982

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7 0
1 year ago
The radar system beeps once every second. How many times will it beep in 3 days?
Colt1911 [192]

Answer:

259200

Step-by-step explanation:

so there are 86400 in one day. multiply by 3.

7 0
3 years ago
Read 2 more answers
Bens score in a game is x points and Olives score is three times that of ben. Their combined point total is -48 points.
andrew-mc [135]
B. The equation is 4x = -48. Ben’s point total is -12.
6 0
2 years ago
A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the cable can hold. Th
Darya [45]

Answer:

The 95%   confidence interval is   768.44  <  \mu

Step-by-step explanation:

From the question we are told that  

    The  sample size is n = 48

    The sample mean is  \= x  =  773 \ lb

     The standard deviation is  \sigma =  16.1 \ lb

   

Now given that the confidence level is  95% , then the level of significance is mathematically represented as

          \alpha  =  100 - 95

          \alpha  =  5 \%

          \alpha  =  0.05

Next we obtain the  critical value of  \frac{\alpha }{2} from the normal distribution table , the value is

              Z_{\frac{\alpha }{2} } = 1.96

The reason we are obtaining critical values of   \frac{\alpha }{2} instead of    \alpha is because  

\alpha represents the area under the normal curve where the confidence level interval (   1-\alpha ) did not cover which include both the left and right tail while

\frac{\alpha }{2}is just the area of one tail which what we required to calculate the margin of error

 The  margin of error is mathematically represented as

      MOE  =  Z_{\frac{\alpha }{2} } *  \frac{\sigma }{ \sqrt{n} }

substituting values

     MOE  =  1.96 *  \frac{ 16.1 }{ \sqrt{48} }

     MOE  =  4.555

The 95% confidence interval to estimate the mean breaking weight for this type cable is mathematically evaluated as

      \= x  - MOE  <  \mu  < \= x  - MOE

substituting values

    773  - 4.555  <  \mu  < 773  + 4.555

     768.44  <  \mu

3 0
3 years ago
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