Answer: y=4
Step-by-step explanation: First of all, we have to know what a consistent and independent system is.
Consistent and independent- If a consistent system has exactly one solution, and is independent, then it's consistent and independent
Let's graph the equation y=3x-2 first. The y intercept of the equation is -2 and the slope of the equation is 3. Lets plot the y intercept first, then use rise/run for the slope. We end off with the image of the first one I have attached to this answer.
Next, we can see if that we draw a straight arrow to one of the points in the equation, we will get a independent and consistent system. I picked y=4, but you can pick almost any point that lies within the line.
This will grant only one solution, which will give us what we need. So let's graph y=4. Finally, we have our consistent and independent system! I've attached another file to support my answer.
So the final answer to your question is y=4, the solution to the system is (2,4), as you can see by the last image.
<em><u> Give me feedback on my answer. Tell me if I'm lacking explanation about anything. Please help me, you can also help others by informing me what else I need to be specific on.</u></em>
Answer:
-27w^9
Step-by-step explanation:
Multiply
-3w^8 × 9w
Step 1:
-3 × 9
= -27
Step 2:
w^8 × w¹
Using the law of indices
w^8 × w¹
= w^(8+1)
= w^9
-3w^8 × 9w
= -27w^9
Keeps 5 salmon for every 8 cods
keel 15 salmon for ?cods
Step 1:
Cross multiply
15×8=120
Step 2:
120÷5=24. As a result, if Phil keeps 15 salmon, he will keep 24 cods. Hope it help!
<span>1) Find the equation of the
line that passes through (x1, y1) and (x3, y3).
We have it: </span>y = 0.4x + 38<span>2) Find the equation of the
line parallel to the previous line that passes through (x2, y2).
</span><span>That is: y = 0.4x + 59
</span><span>3) Find the weighted
average of the
y-intercepts. b=(b1+b2+b1)/3 = (38+59+38)/3
b= 45
The median-median line is the line parallel to the previous two lines with the weighted y-intercept.Hence, Y = 0.4 x + 45 is the answer</span>