Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
Make each a ratio, and set them equal to each other.
Larger rectangle = 3/5
smaller rectangle = x/3
3/5 = x/3
cross multiply
3/5(5)(3) = x/3(3)(5)
3(3) = x(5)
9 = 5x
Isolate the x, divide 5 from both sides
9/5 = 5x/5
x = 9/5
x = 1.8
1.8 in. is your answer
hope this helps
Answer:
1 milliliter is 20 drops.
Is one of the answer choices no solution because that’s what I got.
Answer:
Step-by-step explanation:
12/(x+2) = 4/(x-2)
Cross-multiply to get:
12x-24 = 4x+8
8x = 32
x = 4
