We're finding the function of (p+3), which means wherever there's an x, we're replacing it with (p+3).
2 (p+3)^2 + 3 (p+3) + 6
Foil out (p+3)^2.
2 (p^2 + 6p + 9) + 3 (p+3) + 6
Distribute.
2p^2 + 12p + 18 + 3p + 9 + 6
Add like terms.
g (p+3) = 2p^2 + 15p + 33
If I get this it should be, 25 x 12 = 300, think it as 4 x 25 is 100 so you need 3 x 100, so 4 x 3 is 12, 25 x 12 =12, hope this helps
Think about this as a table of values where domain is the x values and range is the y values.
f(4) wants the y-value when the x-value is 4
f(4) = 1/2
The second question wants us to find the x-value when f(x) also known as the y-value is 4.
f(x) = 4
x = 8
answers: 1/2, 8
Answer:
YES
Step-by-step explanation:
because they are all different lengths
2x+y=-4
5x+3y=-6
multiply first equaton by -5 and second by 2 then add them
-10x-5y=20
<u>10x+6y=-12 +</u>
0x+1y=8
y=8
the y value is 8