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seropon [69]
2 years ago
5

x and y are numbers between 50 and 100. Both x and y have the same digit but in a different order. the two numbers add up to 187

all their digits add up to 34. find x and y.
Mathematics
1 answer:
Ymorist [56]2 years ago
6 0

By solving a system of equations, we see that:

x = 89 and y = 98.

<h3>How to find the two numbers?</h3>

First, we can write:

x = a*10 + b

y = b*10 + c

Where a, b, and c are single digit numbers. You can see that b is on both numbers because we know that the numbers share a digit, but on different order.

We also know that:

x + y = 187

a + b + b + c = 34

I we rewrite the first equation, we get:

(a*10 + b) + (b*10 + c) = 187

10a + 11b + c = 187

Then we have two equations:

a + 2b + c = 34

10a + 11b + c = 187

In both equations we can isolate c:

34 -2b -a = c

10a + 11b - 187 = c

Now we have:

-a - 2b + 34  = -10a - 11b + 187

Solving that, we get:

9a + 9b = 153

a + b = 153/9 = 17

Then a and b add up to 17, we can take:

a = 8

b = 9

And:

c = -a - 2b + 34 = -8 - 9 - 9 + 34 = 8

Then the numbers are:

x = 89

y = 98

If you want to learn more about system of equations:

brainly.com/question/13729904

#SPJ1

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The proportion of students in a psychology experiment who could remember an eight-digit number correctly for t minutes was 0.9 −
kaheart [24]

Answer:

The proportion would be 0.1

Step-by-step explanation:

Given, the function that shows the proportion of students in a psychology experiment who could remember an eight-digit number correctly for t minutes,

f(t) = 0.9 - 0.4\ln(t)

If t = 7 minutes,

f(7) = 0.9 - 0.4\ln(7)=0.9 - 0.77836=0.12164\approx 0.1

Hence, the proportion that remembered the number for 7 minutes is 0.1 ( approx )

8 0
3 years ago
A rectangular box without a lid is to be made from 48 m2 of cardboard. Find the maximum volume of such a box. SOLUTION We let x,
tatiyna

Answer:

The maximum volume of such box is 32m^3

V = x×y×z = 32 m^3

Step-by-step explanation:

Given;

Total surface area S = 48m^2

Volume of a rectangular box V = length×width×height

V = xyz ......1

Total surface area of a rectangular box without a lid is

S = xy + 2xz + 2yz = 48 .....2

To be able to maximize the volume, we need to reduce the number of variables.

Let assume the rectangular box has a square base,that means; length = width

x = y

Substituting y with x in equation 1 and 2;

V = x^2(z) ....3

x^2 + 4xz = 48 .....4

Making z the subject of formula in equation 4

4xz = 48 - x^2

z = (48 - x^2)/4x .......5

To be able to maximize V, we need to reduce the number of variables to 1, by substituting equation 5 into equation 3

V = x^2 × (48 - x^2)/4x

V = (48x - x^3)/4

differentiating V with respect to x;

V' = (48 - 3x^2)/4

At the maximum point V' = 0

V' = (48 - 3x^2)/4 = 0

Solving for x;

3x^2 = 48

x = √(48/3)

x = √(16)

x = 4

Since x = y

y = 4

From equation 5;

z = (48 - x^2)/4x

z = (48 - 4^2)/4(4)

z = 32/16

z = 2

The maximum volume can be derived by substituting x,y,z into equation 1;

V = xyz = 4×4×2 = 32 m^3

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4 years ago
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xxMikexx [17]

Answer:

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