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seropon [69]
2 years ago
5

x and y are numbers between 50 and 100. Both x and y have the same digit but in a different order. the two numbers add up to 187

all their digits add up to 34. find x and y.
Mathematics
1 answer:
Ymorist [56]2 years ago
6 0

By solving a system of equations, we see that:

x = 89 and y = 98.

<h3>How to find the two numbers?</h3>

First, we can write:

x = a*10 + b

y = b*10 + c

Where a, b, and c are single digit numbers. You can see that b is on both numbers because we know that the numbers share a digit, but on different order.

We also know that:

x + y = 187

a + b + b + c = 34

I we rewrite the first equation, we get:

(a*10 + b) + (b*10 + c) = 187

10a + 11b + c = 187

Then we have two equations:

a + 2b + c = 34

10a + 11b + c = 187

In both equations we can isolate c:

34 -2b -a = c

10a + 11b - 187 = c

Now we have:

-a - 2b + 34  = -10a - 11b + 187

Solving that, we get:

9a + 9b = 153

a + b = 153/9 = 17

Then a and b add up to 17, we can take:

a = 8

b = 9

And:

c = -a - 2b + 34 = -8 - 9 - 9 + 34 = 8

Then the numbers are:

x = 89

y = 98

If you want to learn more about system of equations:

brainly.com/question/13729904

#SPJ1

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Answer:

Step-by-step explanation:

Given that A = {2, 4, 6}, B = {2, 6}, C = {4, 6}, and D = {4, 6, 8}.

We know that P is a subset of Q if all elements of P are also in Q

Using this let us compare pairwise

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SO answer is

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Isaac played a video game 20 times and wont about 70% of the games. how many games did he win
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We know that Isaac played 20 games and won about 70% of them. Now, we must find what 70% of 20 is, so that we know how many games Isaac won.

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