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1 year ago

Middle school problem attached :D

Mathematics

2 answers:

Romashka-Z-Leto [24]1 year ago

8 0

$638.40 left over :]

suter [353]1 year ago

7 0

Answer: $638.40

Step-by-step explanation:

45% converted to a decimal is 0.45

0.45 of $1200 = 0.45* $1200 (of in this case means multiply)

0.45 * $1200= $440

Because they said 11% of remaining salary, we have to do:

$1200-$440=$760

Now 11% converted to a decimal is 0.11

5% converted to a decimal is 0.05

So 0.11+0.05

0.11+0.05= 0.16

Now 0.16 *$760=$121.60

Now we find the remaining amount so we subtract: $760-$121.60= $638.40

So our answer is $638.40 left

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A piggy bank contains 80 nickels and dimes the value of the coins is 5.15

dimaraw [331]

Answer: the amount of dimes is $1.15 this is also equivalent to 11 dimes and an extra nickel.

Explanation:

80 nickels =$4.00
$5.15-$4.00= $1.15
11 dimes= $1.10
1 nickel= $0.05
$1.10+$0.05= $1.15

hope this helps! :)

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3 years ago

What is the total surface area

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3 years ago

Question 4 options:

IgorLugansk [536]

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3 years ago

What function is increasing? will give brainlist !

Wewaii [24]

Answer:

Option B.

Step-by-step explanation:

Option A.

f(x) = $(0.5)^{x}$

Derivative of the given function,

f'(x) = $\frac{d}{dx}(0.5)^x$

= $(0.5)^x[\text{ln}(0.5)]$

= $-(0.693)(0.5)^{x}$

Since derivative of the function is negative, the given function is decreasing.

Option B. f(x) = $5^x$

f'(x) = $\frac{d}{dx}(5)^x$

= $(5)^x[\text{ln}(5)]$

= $1.609(5)^x$

Since derivative is positive, given function is increasing.

Option C. f(x) = $(\frac{1}{5})^x$

f'(x) = $\frac{d}{dx}(\frac{1}{5})^x$

= $\frac{d}{dx}(5)^{(-x)}$

= $-5^{-x}.\text{ln}(5)$

Since derivative is negative, given function is decreasing.

Option D. f(x) = $(\frac{1}{15})^x$

f'(x) = $-15^{-x}[\text{ln}(15)]$

= $-2.708(15)^{-x}$

Since derivative is negative, given function is decreasing.

Option (B) is the answer.

7 0

2 years ago

Select the pair of slopes that are the slopes of perpendicular lines.

agasfer [191]

<h3> $\frac{3}{4}\ and\ \frac{-4}{3}$ are the slopes of perpendicular lines</h3>

Solution:

We know that,

Product of slope of a line and slope of line perpendicular to it is always equal to -1

Option 1

$\frac{1}{2}\ and\ 2$

$Product = \frac{1}{2} \times 2 = 1$

Thus, these are not the slopes of perpendicular lines

Option 2

$\frac{3}{4}\ and\ \frac{-4}{3}\\\\Product = \frac{3}{4} \times \frac{-4}{3}\\\\Product = -1$

This option satisfies the slopes of perpendicular lines

Option 3

$\frac{-2}{5}\ and\ \frac{-5}{2}\\\\Product = \frac{-2}{5} \times \frac{-5}{2} = 1$

Thus, these are not the slopes of perpendicular lines

Option 4

2 and 2

Product = 2 x 2 = 4

Thus, these are not the slopes of perpendicular lines

7 0

3 years ago