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2 years ago

Simplify (20^13)^19 A. 400^32 B. 20^32 C. 20^247 D. 400^247

1 answer:

5 0

When an exponent is outside the parenthesis, you multiply them.

13*19=247

“C” 2^247 is the answer.

I hope this helps!
~kaikers

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Associations In Data:Question 10

Karo-lina-s [1.5K]

Answer:

$\bar X = \frac{62+63+68+72+79+80+83+93+94+95}{10}= 78.9$

$|62-78.9| = 16.9$

$|63-78.9| = 15.9$

$|68-78.9| = 10.9$

$|72-78.9| = 6.9$

$|79-78.9| = 0.1$

$|80-78.9| = 1.1$

$|83-78.9| = 4.1$

$|93-78.9| = 14.1$

$|94-78.9| = 15.1$

$|95-78.9| = 16.1$

$MAD = \frac{\sum_{i=1}^n |X_i -\bar X|}{n}$

And replacing we got:

$MAD =\frac{16.9+15.9+10.9+6.9+0.1+1.1+4.1+14.1+15.1+16.1}{10}= 10.12$

And the best anwer is

10.12

Step-by-step explanation:

We have the following data given:

62 63 68 72 79 80 83 93 94 95

And we need to begin finding the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And replacing we got:

$\bar X = \frac{62+63+68+72+79+80+83+93+94+95}{10}= 78.9$

Now we can find the mean absolute deviation like this:

$|62-78.9| = 16.9$

$|63-78.9| = 15.9$

$|68-78.9| = 10.9$

$|72-78.9| = 6.9$

$|79-78.9| = 0.1$

$|80-78.9| = 1.1$

$|83-78.9| = 4.1$

$|93-78.9| = 14.1$

$|94-78.9| = 15.1$

$|95-78.9| = 16.1$

And finally we can find the mean abslute deviation with the following formula:

$MAD = \frac{\sum_{i=1}^n |X_i -\bar X|}{n}$

And replacing we got:

$MAD =\frac{16.9+15.9+10.9+6.9+0.1+1.1+4.1+14.1+15.1+16.1}{10}= 10.12$

And the best anwer is

10.12

8 0

3 years ago

Please help with #22! You don’t have to fully explain.

trasher [3.6K]

The answer to the first part is 3 1/2 and the answer to the second question is 2/7

3 0

2 years ago

Suppose the claim size of an auto collision insurance, X, is uniformly distributed on the interval $1,000 to $10,000. What is th

timurjin [86]

Answer:

35.35%

Step-by-step explanation:

If there were no deductibles, the expected claim payment would be:

$E(X) = \frac{10,000 +1,000}{2} \\E(X) =\$5,500$

If the collision insurance claim is under $2,000, then the insurer would not pay anything, but if X > $2,000, then the insurer would pay X - $2,000. The new expected value is:

$E_2(X)=\frac{2,000-1,000}{10,000-1,000} *0+\frac{10,000-2,000}{10,000-1,000}*\frac{(2,000-2,000)+(10,000-2,000)}{2} \\E_2(X)=\frac{8}{9}*\frac{0+8,000}{2}\\ E_2(X)=\$3,555.56$