Answer: Assuming the a2 is a with an exponent of 2 and a3 is a with an exponent of 3, the answer is 2a^6-2a^5
Step-by-step explanation: the number after the ^ means to the power of
Indeed you need to speech English
C. negative exponents always go at the bottom
Where's the graph that represents the speed of the sea lion?
Answer:
89.1° or -1.4°
Step-by-step explanation:
1. Location:
You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.
The French troops are about 50 m below you and 1.2 km distant.
2. Finding the firing angle
Data:
R = 1200 m
u = 600 m/s
h = -50 m (the height of the target)
a = 9.8 m/s²
We have two conditions.
Horizontal distance
(1) 1200 = 600t cosθ
Vertical distance
(2) -50 = 600t sinθ - 4.9t²
Divide each side of (1) by 600cosθ.
![(3) \, t =\dfrac{2}{\cos \theta}](https://tex.z-dn.net/?f=%283%29%20%5C%2C%20t%20%3D%5Cdfrac%7B2%7D%7B%5Ccos%20%5Ctheta%7D)
Substitute (3) into (2)
![-50 = 600t \sin \theta - 4.9t^{2} = 600 \left( \dfrac{2}{\cos \theta} \right ) \sin \theta - 4.9 \left( \dfrac{2}{\cos \theta} \right )^{2}\\\\(4) \, -50 = 1200 \tan \theta - \dfrac{19.6}{\cos^{2} \theta}](https://tex.z-dn.net/?f=-50%20%3D%20600t%20%5Csin%20%5Ctheta%20-%204.9t%5E%7B2%7D%20%3D%20%20600%20%5Cleft%28%20%5Cdfrac%7B2%7D%7B%5Ccos%20%5Ctheta%7D%20%5Cright%20%29%20%5Csin%20%5Ctheta%20-%204.9%20%5Cleft%28%20%5Cdfrac%7B2%7D%7B%5Ccos%20%5Ctheta%7D%20%5Cright%20%29%5E%7B2%7D%5C%5C%5C%5C%284%29%20%5C%2C%20-50%20%3D%201200%20%5Ctan%20%5Ctheta%20-%20%5Cdfrac%7B19.6%7D%7B%5Ccos%5E%7B2%7D%20%5Ctheta%7D)
Recall that
(5) sec²θ = 1/cos²θ = tan²θ + 1
Substitute (5) into (4)
![-50 = 1200 \tan \theta - 19.6 \left(\tan^{2} \theta}+ 1\right )](https://tex.z-dn.net/?f=-50%20%3D%201200%20%5Ctan%20%5Ctheta%20-%2019.6%20%5Cleft%28%5Ctan%5E%7B2%7D%20%5Ctheta%7D%2B%201%5Cright%20%29)
Set up a quadratic equation
![\begin{array}{rcl}-50 & = & 1200 \tan \theta - 19.6\tan^{2} \theta -19.6 \\0 & = & 1200 \tan \theta - 19.6\tan^{2} \theta + 30.4\\0 & =&19.6\tan^{2} \theta - 1200 \tan \theta - 30.4\\0 & =&\tan^{2} \theta - 61.224 \tan \theta - 1.551\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D-50%20%26%20%3D%20%26%201200%20%5Ctan%20%5Ctheta%20-%2019.6%5Ctan%5E%7B2%7D%20%5Ctheta%20-19.6%20%5C%5C0%20%26%20%3D%20%26%201200%20%5Ctan%20%5Ctheta%20-%2019.6%5Ctan%5E%7B2%7D%20%5Ctheta%20%2B%2030.4%5C%5C0%20%26%20%3D%2619.6%5Ctan%5E%7B2%7D%20%5Ctheta%20-%201200%20%5Ctan%20%5Ctheta%20-%2030.4%5C%5C0%20%26%20%3D%26%5Ctan%5E%7B2%7D%20%5Ctheta%20-%2061.224%20%5Ctan%20%5Ctheta%20-%201.551%5C%5C%5Cend%7Barray%7D)
Solve for θ
Use the quadratic formula.
tanθ = 61.249 or -0.025
θ = arctan(61.249) = 89.1° or
θ = arctan(-0.025) = -1.4°