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Firdavs [7]
3 years ago
15

15 POINTS! What is the correct answer for Dean's problem? Explain where he went wrong.

Mathematics
1 answer:
prohojiy [21]3 years ago
8 0

Answer:

The slope is 5/-2.

Step-by-step explanation:

Slope is y1-y2 over m1-m2 (rise over run). The first ordered pair is -2 (m1) and 11 (y1). We then subtract the second ordered pair (4 (m2) and -4 (y2)) from the first.

11 - (-4) = 11 + 4 = 15

-2 - 4 = -6

Remember, slope is rise over run (y over x), so the slope is 15/-6. Now, we must simplify. 15/-6 = 5/-2

Dean went wrong because he thought that slope was run over rise (x over y). If he had switched the two numbers, his answer would have been correct.

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Answer: =23

Step-by-step explanation:

4+23-\left|-4\right|

=4+23-4

=23

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3+2 I don't know why they expect a kindergartener to do this hard work
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The answer is 5!  Like if you have 3 cookies then add two you would have .. 5!  (: any other questions you need help with?
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Use the model below to estimate the average annual growth rate of a certain country's population for 1950, 1988, and 2010, where
Morgarella [4.7K]

Answer:

The average annual growth rate of a certain country's population for 1950, 1988, and 2010 are 2.398, 0.9985 and 0.2236 respectively.

Step-by-step explanation:

The given equation is

Y=-0.0000084x^3+0.00211x^2-0.205x+8.423

Where Y is the annual growth rate of  a certain country's population and x is the number of years after 1900.

Difference between 1950 and 1900 is 50.

Put x=50 in the given equation.

Y=-0.0000084(50)^3+0.00211(50)^2-0.205(50)+8.423

Y=2.398

Therefore the estimated average annual growth rate of the country's population for 1950 is 2.398.

Difference between 1988 and 1900 is 88.

Put x=88 in the given equation.

Y=-0.0000084(88)^3+0.00211(88)^2-0.205(88)+8.423

Y=0.9984752\approx 0.9985

Therefore the estimated average annual growth rate of the country's population for 1988 is 0.9985.

Difference between 2010 and 1900 is 110.

Put x=110 in the given equation.

Y=-0.0000084(110)^3+0.00211(110)^2-0.205(110)+8.423

Y=0.2236

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8 0
2 years ago
Let v1=(3,5) and v2=(-4,7).
Nat2105 [25]
PART A

The given vectors are,

v_1 = \: < \: 3 , \: 5 \: >

v_2 = \: < \: - 4 , \: 7 \: >

The magnitude of the vector

v= \: < \: x , \: y \: > \:

is given by:

|v| = \sqrt{ {x}^{2} + {y}^{2} }

This implies that,

|v_1| = \sqrt{ {3}^{2} + {5}^{2} }

|v_1| = \sqrt{9 + 25}

|v_1| = \sqrt{34}

|v_2| = \sqrt{ {( - 4)}^{2} + {7}^{2} }

|v_2| = \sqrt{ 16+ 49}

|v_2| = \sqrt{65}

PART B

To find the unit vector in the direction of a given vector, we divide by the magnitude of that vector.

^{ - } _{v_1} = \: < \: \frac{3}{ \sqrt{34} } , \: \frac{5}{ \sqrt{34} } \: >

Rationalize the denominator.

^{ - } _{v_1} = \: < \: \frac{3\sqrt{34}}{ 34 } , \: \frac{5\sqrt{34}}{ 34 } \: >

Also,

^{ - } _{v_2} = \: < \: \frac{ - 4}{ \sqrt{65} } , \: \frac{7}{ \sqrt{65} } \: >

^{ - } _{v_2} = \: < \: \frac{ - 4\sqrt{65}}{ 65 } , \: \frac{7\sqrt{65}}{ 65 } \: >

PART C

The sketch of the given vectors as well as their unit vectors are shown in the attachment.

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Answer:A

Step-by-step explanation:

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