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Yakvenalex [24]
3 years ago
9

Given a vertical asymptote at x=0 and a horizontal asymptote at y=2, which values of x should be used to determine coordinate?

Mathematics
1 answer:
vodka [1.7K]3 years ago
5 0

The y and a coordinated go left

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Just answer #4 (Trigonometry) THANK YOU!!!
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Opposite over adjacent
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How to solve this integration problem? the answer should be -π/12
ivann1987 [24]
\displaystyle\int_{-1}^{-\sqrt2/2}\frac{\mathrm dy}{y\sqrt{4y^2-1}}

Try setting y=\dfrac12\sec t, so that \mathrm dy=\dfrac12\sec t\tan t\,\mathrm dt. The interval then changes from -1\le y\le-\dfrac{\sqrt2}2 to \dfrac{2\pi}3\le t\le \dfrac{3\pi}4.

Now, the integral is

\displaystyle \int_{2\pi/3}^{3\pi/4} \frac{\dfrac12\sec t\tan t}{\dfrac12\sec t\sqrt{4\left(\dfrac12\sec t\right)^2-1}}\,\mathrm dt=\int_{2\pi/3}^{3\pi/4}\frac{\tan t}{\sqrt{\sec^2t-1}}\,\mathrm dt

The Pythagorean identity lets you reduce the denominator:

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Since \tan t for the given interval, you have |\tan t|=-\tan t, which means the integral is equal to

\displaystyle\int_{2\pi/3}^{3\pi/4}\frac{\tan t}{-\tan t}\,\mathrm dt=-\int_{2\pi/3}^{3\pi/4}\mathrm dt=-\dfrac\pi{12}
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Translate the sentence into an inequality. <br> The product of x and 3 is greater than -25.
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By rearranging this y/x =39.4 ( is the constant speed). don’t forget this is mile/minutes

There are 4 x 60 minutes in 4 hours

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y = 9456 miles
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3 years ago
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