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3 years ago

Help me please help me

Mathematics

2 answers:

Dmitry [639]3 years ago

8 0

Yes its a function the vertical line test is up and down and nothings hitting pls give me brainliest

ziro4ka [17]3 years ago

7 0

Yes it’s a function

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Jane must get at least three of the four problems on the exam correct to get an A. She has been able to do 80% of the problems o

NISA [10]

Answer:

a) There is n 81.92% probability that she gets an A.

b) If she gets the first problem correct, there is an 89.6% probability that she gets an A.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the answer is correct, or it is not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

For this problem, we have that:

The probability she gets any problem correct is 0.8, so $\pi = 0.8$ .

(a) What is the probability she gets an A?

There are four problems, so $n = 4$

Jane must get at least three of the four problems on the exam correct to get an A.

So, we need to find $P(X \geq 3)$

$P(X \geq 3) = P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 3) = C_{4,3}.(0.80)^{3}.(0.2)^{1} = 0.4096$

$P(X = 4) = C_{4,4}.(0.80)^{4}.(0.2)^{0} = 0.4096$

$P(X \geq 3) = P(X = 3) + P(X = 4) = 2*0.4096 = 0.8192$

There is n 81.92% probability that she gets an A.

(b) If she gets the first problem correct, what is the probability she gets an A?

Now, there are only 3 problems left, so $n = 3$

To get an A, she must get at least 2 of them right, since one(the first one) she has already got it correct.

So, we need to find $P(X \geq 2)$

$P(X \geq 3) = P(X = 2) + P(X = 3)$

$P(X = 2) = C_{3,2}.(0.80)^{2}.(0.2)^{1} = 0.384$

$P(X = 4) = C_{3,3}.(0.80)^{3}.(0.2)^{0} = 0.512$

$P(X \geq 3) = P(X = 2) + P(X = 3) = 0.384 + 0.512 = 0.896$

If she gets the first problem correct, there is an 89.6% probability that she gets an A.

3 0

3 years ago

There are 4 such boxes containing toffee and mints Mary take 8 toffees and 26 mints from the boxes what is the ratio of the numb

Anettt [7]

Answer:

4:13

Step-by-step explanation:

Ratio expresses the relationship between two or more numbers. It shows the frequency of the number of times that one value is contained within other value(s).

8 : 26

divide each number by 2

4 : 13

5 0

2 years ago

A plane descends 1000 ft while flying<br> 2.7 mi. What is the angle of descent?

Murrr4er [49]

Answer:

4.02°

Step-by-step explanation:

The angle of descent can be obtained using trigonometry ;

Since we have a right angled triangle ;

Let's use the relation:

Sin θ = opposite / hypotenus

Hypotenus = 2.7 miles

1 mile = 5280 feets

2.7 miles = (2.7 * 5280) = 14256 feets

Sin θ = 1000 / 14256

Sin θ = 0.0701459

θ = sin^-1(0.0701459)

θ = 4.0223674

3 0

3 years ago

Show that the maximum rate of change, with respect to radius, of the volume of a deflating balloon is four times the sphere's in

dmitriy555 [2]

Step-by-step explanation:

Let's say R is the initial radius of the sphere, and r is the radius at time t.

The volume of the sphere at time t is:

V = 4/3 π r³

Taking derivative with respect to radius:

dV/dr = 4π r²

This is a maximum when r is a maximum, which is when r = R.

(dV/dr)max = 4π R²

This is 4 times the sphere's initial great circle area, but not the great circle circumference. The problem statement contains an error.

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3 years ago

Name Date 1. Create a scale drawing of the picture below using a scale factor of 60%. Write three equations that show how you de

adelina 88 [10]

Answer:

60 9 is answerrr..........

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3 years ago