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2 years ago

Pls the explanation of archimedes principle

Physics

1 answer:

My name is Ann [436]2 years ago

5 0

Explanation:

Hello !

<h2>Archimedes' principle</h2>

''states that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially, is equal to the weight of the fluid that the body displaces.''

Archimedes principle equation is given as

buoyant force = density of fluid x volume of displaced fluid x acceleration due to gravity. or

<em>Fb=-density*gravity*volume </em>

<em>For example,</em> a ship that is launched sinks into the ocean until the weight of the water it displaces is just equal to its own weight.

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a bat experts a 120 N force on a 0.134 kg baseball for 0.04 seconds. what impolse is excerted on the bat

musickatia [10]

The impulse exerted by a force F on an object in a time $\Delta t$ is given by
$I = F \Delta t$
In our problem, we have a force of 120 N: F=120 N, applied to the baseball for a time of $\Delta t=0.04 s$ . Therefore the impulse is
$I=F \Delta t = (120 N)(0.04 s)=4.8 Ns$

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4 years ago

While studying projectile motion, we consider ideal scenarios, where the projectile travels along its trajectory only under the

Law Incorporation [45]

Drag is usually ignored because its effect on the horizontal velocity is usually negligible due to the short time of flight.

An object's surface area and geometry, along with the object's surrounding wind speed will affect the drag force.

In most cases, drag force will cause the object to land horizontally closer to the predicted landing point as drag is a resistive force.

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3 years ago

Read 2 more answers

The nucleus of an atom can be modeled as several protons and neutrons closely packed together. Each particle has a mass of 1.67

Lady bird [3.3K]

Explanation:

The nucleus of an atom can be modeled as several protons and neutrons closely packed together.

Mass of the particle, $m=1.67\times 10^{-27}\ kg$

Radius of the particle, $R=10^{-15}\ m$

(a) The density of the nucleus of an atom is given by mass per unit area of the particle. Mathematically, it is given by :

$d=\dfrac{m}{V}$ , V is the volume of the particle

$d=\dfrac{m}{(4/3)\pi r^3}$

$d=\dfrac{1.67\times 10^{-27}}{(4/3)\pi (10^{-15})^3}$

$d=3.98\times 10^{17}\ kg/m^3$

So, the density of the nucleus of an atom is $3.98\times 10^{17}\ kg/m^3$ .

(b) Density of iron, $d'=7874\ kg/m^3$

Taking ratio of the density of nucleus of an atom and the density of iron as :

$\dfrac{d}{d'}=\dfrac{3.98\times 10^{17}}{7874}$

$\dfrac{d}{d'}=5.05\times 10^{13}$

$d=5.05\times 10^{13}\ d'$

So, the density of the nucleus of an atom is $5.05\times 10^{13}$ times greater than the density of iron. Hence, this is the required solution.

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4 years ago

The inhabitants of a small island export a cloth made from a plant that grows only on their island. A clothier from New York, be

Inessa [10]

Answer:

Explanation:

purchase price = 400 tepizes / m²

1 tepiz = .625 dollar

purchase price in terms of dollar = 400 x .625 dollar / m²

= 250 dollar / m²

.9144 m = 1 yard

1 m = 1.0936 yard

1m² = 1.196 yard²

price in terms of dollar / yards²

= 250 / 1.196 dollar / yard²

= 209 dollar / yard²

Price of cloth in New York = 120 dollar / yard²

loss = 209 - 120 = 89 dollar / yard²

500 m² = 500 x 1.196 yard²

= 598 yard²

net loss in purchasing 500 m² cloth

= 598 x 89

= 53222 dollar .

7 0

4 years ago

#27 question

Furkat [3]

So, the initial altitude of the parachuter is approximately <u>(C). 123 m</u>.

<h2>Introduction</h2>

Hi ! In this question, I will help you. In this question, you will learn about the fall time of the free fall motion. Free fall is a downward vertical motion without being preceded by an initial velocity. When moving in free fall, the following equations apply:

<h3>The equation for calculating the height (h)</h3>

$\boxed{\sf{\bold{h = \frac{1}{2} \cdot g \cdot t^2}}}$

<h3>The equation for calculating the time (s)</h3>

$\boxed{\sf{\bold{t = \sqrt{\frac{2 \cdot h}{g}}}}}$

<h3>The equation for calculating the velocity (v)</h3>

$\boxed{\sf{\bold{v = \sqrt{2 \times g \times h}}}}$

With the following condition :

t = interval of the time (s)
h = height or any other displacement at vertical line (m)
g = acceleration of the gravity (m/s²)
v = velocity (m/s)

<h2>Problem Solving</h2>

We know that :

t = interval of the time = 5 s
g = acceleration of the gravity = 9.81 m/s²

What was asked :

h = height or displacement at vertical line = ... m

Step by Step :

$\sf{h = \frac{1}{2} \cdot g \cdot t^2}$

$\sf{h = \frac{1}{2} \cdot 9.81 \cdot 5^2}$

$\sf{h = \frac{245.25}{2}}$

$\boxed{\sf{h = 122.625 \: m \approx 123 \: m}}$

<h3>Conclusion</h3>

So, the initial altitude of the parachuter is approximately 123 m (C.)

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2 years ago