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Goryan [66]
3 years ago
14

Which expression is equivalent to 15x – 2(3x + 6)?

Mathematics
1 answer:
lakkis [162]3 years ago
5 0

Answer:

35x+12

Step-by-step explanation:

1. You combine like terms. (15x *3x=35x)

2.You Multiply other terms (2*6= 12)

3. Answer: 35x+12

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Please help me! in need of help due tomorrow!​
julsineya [31]

Answer:

Step-by-step explanation:

(1). A = π r²

A = 4 π

Area of shaded region is \frac{4\pi *260}{360} = \frac{26}{9} \pi or \frac{26\pi }{9}

(2). C = 4 π

In this case, the length of the bigger arc and the area of shaded region happen to be the same.

The length of the arc ADB is  \frac{26}{9} \pi or \frac{26\pi }{9}

3 0
1 year ago
Solve the linear equation by using the Gauss-Jordan elimination method
Paha777 [63]

Answer:  ( x , − x/ 3 − 5 /3 )

Step-by-step explanation:


7 0
3 years ago
Write a two column proof
Annette [7]

4y=2x-10 and y=6

use the second expression to calculate the left-hand side of the first equation:

4\cdot 6 = 2x -10\\24 = 2x -10

Add 10 to both sides if this equation to get

34 = 2x

and divide both sides by 2

17 = x

this proves that x = 17, give the two initial equations

8 0
3 years ago
Robert is looking at purchasing bonds to diversify his portfolio and must decide which type of bonds to purchase. Which type of
dedylja [7]

Answer:

I just took the test and it is municipal bonds.

Step-by-step explanation:

3 0
3 years ago
Let $f(x) = 2x^2 + 3x - 9,$ $g(x) = 5x + 11,$ and $h(x) = -3x^2 + 1.$ Find $f(x) - g(x) + h(x).$
Viefleur [7K]

QUESTION 1

Given that:

f(x)=2x^2+3x-9,

g(x)=5x+11,

and

h(x)=-3x^2+1

Then;

f(x)-g(x)+h(x)=2x^2+3x-9-(5x+11)+(-3x^2+1)

f(x)-g(x)+h(x)=2x^2+3x-9-5x-11-3x^2+1

Group similar terms;

f(x)-g(x)+h(x)=2x^2-3x^2+3x-5x-11-9+1

Simplify;

f(x)-g(x)+h(x)=-x^2-2x-19

QUESTION 2

Given that;

f(x)=4x-7.

g(x)=(x+1)^2

and

s(x)=f(x)+g(x)

Substitute the functions;

s(x)=4x-7+(x+1)^2

Substitute x=3

s(3)=4(3)-7+(3+1)^2

s(3)=12-7+(4)^2

s(3)=5+16

s(3)=21

QUESTION 3

Given:

f(x)=3x+2

g(x)=x^2-5x-1

f(g(x))=f(x^2-5x-1)

This implies that;

f(g(x))=3(x^2-5x-1)+2

Expand the parenthesis;

f(g(x))=3x^2-15x-3+2

f(g(x))=3x^2-15x-1

QUESTION 4

The given function is;

f(x)=3(x-6)^2+1

Let

y=3(x-6)^2+1

\Rightarrow y-1=3(x-6)^2

\Rightarrow \frac{y-1}{3}=(x-6)^2

\Rightarrow \sqrt{\frac{y-1}{3}}=x-6

\Rightarrow x=6+\sqrt{\frac{y-1}{3}}

The range is:

\frac{y-1}{3}\ge0

y-1\ge0

y\ge1

The interval notation is;

[1,+\infty)

6 0
3 years ago
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