Answer:
is a subset of 
Step-by-step explanation:
Required
Difference between subset and proper subset
To answer this question, I will use the following illustration.



In the above sets, set B is a proper subset of set A because all elements of B can be found in A, but not element of A can be found in B.
Set C is a subset of A because 
Using the above illustration, we have:
and 
is a subset of
, because 5 and 8 are in
but 2 which ca be found in
is not in 
Answer:
it would be 17
Step-by-step explanation:
Answer:
When we have a rational function like:

The domain will be the set of all real numbers, such that the denominator is different than zero.
So the first step is to find the values of x such that the denominator (x^2 + 3) is equal to zero.
Then we need to solve:
x^2 + 3 = 0
x^2 = -3
x = √(-3)
This is the square root of a negative number, then this is a complex number.
This means that there is no real number such that x^2 + 3 is equal to zero, then if x can only be a real number, we will never have the denominator equal to zero, so the domain will be the set of all real numbers.
D: x ∈ R.
b) we want to find two different numbers x such that:
r(x) = 1/4
Then we need to solve:

We can multiply both sides by (x^2 + 3)


Now we can multiply both sides by 4:


Now we only need to solve the quadratic equation:
x^2 + 3 - 4*x - 4 = 0
x^2 - 4*x - 1 = 0
We can use the Bhaskara's formula to solve this, remember that for an equation like:
a*x^2 + b*x + c = 0
the solutions are:

here we have:
a = 1
b = -4
c = -1
Then in this case the solutions are:

x = (4 + 4.47)/2 = 4.235
x = (4 - 4.47)/2 = -0.235
Answer:8(1/2x - 1/4)> 12 - 2x
a.x > 7
b.x > 7/3
c.x > 5/3
d.x > 5/3
Step-by-step explanation: Solve the inequality 12(1/2x-1/3)>8-2x
Possible outcomes: 5040
Possible to begin with a 0: 504
Theoretical probability: 0.1
These are the correct answers