For question 1)
During the 8-9 , Mr hare travel 40miles
For the time 9 onwards they travel concurrently,
Let x be the distance covered by both since they can only meet if they covered the sams distance,
x/50 = x/40 -1 ,where the 1 is the (8-9) 1 hr
x/40 - x/50 = 1
x = 200
Time take by Mr Hare = 200/ 40 = 5
from 8 add 5 hours will be 1
ans is b
2)
during 8- 9 hare travelled 50miles
let x be the distance
x/55= x/50-1
x/50-x/55=1
x=550miles
time taken by hare = 550/50=11 hr
ie when they first meet it will be 7pm
so ans is b 8
Answer:
40
Step-by-step explanation:
so next year her money would be 6% more so:
5000 + (0.6 * 5000) = (1.06) * 5000
So each year she'll have : (1.06)*(last year's money)
So we can say after n years she will have :
((1.06)^n) * 5000
So:
5000((1.06)^n)=50000
n is 39.5
So around 40
Answer:
Y=4
Step-by-step explanation:
Because the two triangles are congruent you can set the two expressions equal to each other and solve from their.
step 1 ) 8Y = 6Y + 8
step 2 ) isolate the variable to one side 8Y-6Y= 8 => 2Y = 8
step 3 ) solve for Y 2Y/2 = 8/2
Solution Y=4
