If (4x-y,x-4y):(3,-3y) then find the value of x and y? please help me!
1 answer:
Answer:
- x=1
- y=1
Step-by-step explanation:
This looks like it is intended to represent two equations. They can be solved as a system in any of the usual ways.
The two equations seem to be ...
- 4x -y = 3
- x -4y = -3y
Adding 4y to the second equation gives ...
x -4y +4y = -3y +4y
x = y . . . . . . . . simplify
Substituting for y in the first equation gives ...
4x -x = 3
3x = 3 . . . . simplify
x = 1 . . . . . divide by 3
y = 1 . . . . . same as x
The variables x and y both have a value of 1.
__
The attachment shows a graphical solution to these equations.
You might be interested in
Answer:
d
Step-by-step explanation:
We know that diagonals bisect angles of a rhombus, meaning that they split the angles of two equal parts, that opposite angles are equal, and that the angles of a quadrilateral, such as a rhombus, add up to 360 degrees.
Looking at the drawing I uploaded, and taking into account that diagonals bisect angles of a rhombus, we can say that angle x = y and z = 5x-18
Next, given that opposite angles are equal, we can say that angle B = angle D and angle A = angle C. Therefore,
A+B+C+D= 360 (as the angles of a quadrilateral add up to 360)
A + B + A + B = 360 (plugging in A for C and B for D)
2 ( A + B) = 360
A + B = 180
x + y + z + 5x - 18 = 180 (plugging x+y in for A, and z+5x-18 in for B, as x and y make up A and z and 5x-18 make up B)
x+x+5x-18+5x-18 = 180 (because x=y and z=5x-18)
2(x+5x-18) = 180
divide both sides by 2
x+5x-18=90
6x-18=90
add 18 to both sides
6x=108
divide both sides by 6
x = 18
